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A solution of A and B with 30 mole percent of A is in equilibrium with its vapour which contains 60 mole percent of A . Assuming ideality of the solution and the vapour , the vapour pressure of pure A to that of pure B is?
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Problem: Find the vapour pressure of pure A to that of pure B when a solution of A and B with 30 mole percent of A is in equilibrium with its vapour which contains 60 mole percent of A. Assume ideality of the solution and the vapour.
Solution:
Solution:
- Understand the problem: We are given a solution of A and B with a certain mole fraction of A in equilibrium with its vapour which also has a certain mole fraction of A. We need to find the vapour pressure of pure A to that of pure B.
- Apply Raoult's law: Raoult's law states that the partial vapour pressure of each component in a solution is proportional to its mole fraction in the solution. Mathematically, PA = XAP0A and PB = XBP0B, where PA and PB are the partial vapour pressures of A and B respectively, XA and XB are their mole fractions in the solution, and P0A and P0B are the vapour pressures of pure A and B respectively.
- Use the given information: We are given that the solution has 30 mole percent of A and the vapour has 60 mole percent of A. This means that XA = 0.3 and XB = 0.7 in the solution, and XA = 0.6 and XB = 0.4 in the vapour.
- Find the ratio of vapour pressures: We can use Raoult's law to find the ratio of partial vapour pressures of A and B. PA/PB = (XAP0A)/(XBP0B) = (0.3P0A)/(0.7P0B). We can simplify this expression by assuming that the total pressure of the system is 1 atm, which means that PA + PB = 1 atm. This gives us PB = 1 - PA. Substituting this in the previous expression, we get PA/(1 - PA) = (0.3P0A)/(0.7P0B).
- Solve for P0A/P0B: Rearranging the previous expression, we get P0A/P0B
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A solution of A and B with 30 mole percent of A is in equilibrium with its vapour which contains 60 mole percent of A . Assuming ideality of the solution and the vapour , the vapour pressure of pure A to that of pure B is?
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A solution of A and B with 30 mole percent of A is in equilibrium with its vapour which contains 60 mole percent of A . Assuming ideality of the solution and the vapour , the vapour pressure of pure A to that of pure B is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A solution of A and B with 30 mole percent of A is in equilibrium with its vapour which contains 60 mole percent of A . Assuming ideality of the solution and the vapour , the vapour pressure of pure A to that of pure B is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution of A and B with 30 mole percent of A is in equilibrium with its vapour which contains 60 mole percent of A . Assuming ideality of the solution and the vapour , the vapour pressure of pure A to that of pure B is?.
A solution of A and B with 30 mole percent of A is in equilibrium with its vapour which contains 60 mole percent of A . Assuming ideality of the solution and the vapour , the vapour pressure of pure A to that of pure B is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A solution of A and B with 30 mole percent of A is in equilibrium with its vapour which contains 60 mole percent of A . Assuming ideality of the solution and the vapour , the vapour pressure of pure A to that of pure B is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution of A and B with 30 mole percent of A is in equilibrium with its vapour which contains 60 mole percent of A . Assuming ideality of the solution and the vapour , the vapour pressure of pure A to that of pure B is?.
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