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A convex lens has a focal length of 30 cm. calculate at what distance of the object from the lens if the image is to be formed on the opposite side of the lens at a distance of 75 cm from the lens. What will be the nature of the image?
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A convex lens has a focal length of 30 cm. calculate at what distance ...
Focal Length of Convex Lens:
The given convex lens has a focal length of 30 cm. The focal length of a lens is the distance between the lens and the point where the light rays converge or appear to diverge from. In the case of a convex lens, the focal length is positive.

Distance of the Object from the Lens:
To calculate the distance of the object from the lens, we can use the lens formula:

1/f = 1/v - 1/u

Where f is the focal length, v is the distance of the image from the lens, and u is the distance of the object from the lens.

Distance of the Image from the Lens:
Given that the image is formed on the opposite side of the lens at a distance of 75 cm from the lens, we can substitute these values into the lens formula:

1/30 = 1/75 - 1/u

Simplifying the equation, we get:

1/u = 1/30 - 1/75

To add the fractions, we need a common denominator:

1/u = (5 - 2)/150

1/u = 3/150

Cross-multiplying the equation, we get:

u = 150/3

u = 50 cm

Therefore, the distance of the object from the lens is 50 cm.

Nature of the Image:
To determine the nature of the image formed by the convex lens, we can use the magnification formula:

m = -v/u

Where m is the magnification, v is the distance of the image from the lens, and u is the distance of the object from the lens.

Substituting the given values:

m = -75/50

m = -1.5

The negative sign in the magnification indicates that the image formed by the convex lens is inverted. The magnitude of the magnification is greater than 1, which means that the image is magnified.

Therefore, the nature of the image formed by the convex lens is inverted and magnified.
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A convex lens has a focal length of 30 cm. calculate at what distance of the object from the lens if the image is to be formed on the opposite side of the lens at a distance of 75 cm from the lens. What will be the nature of the image?
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