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A 0.016 M of an acid solution in benzene in dropped on a water surface , the benzene evaporates and the acid form a monomolecular flim of solid type . What volume of the above solution would be required to cover a 500 cm square surface area of water with a monomolecular layer of acid . The area covered by a single acid molecule is 0.2 nm?
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A 0.016 M of an acid solution in benzene in dropped on a water surface...
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A 0.016 M of an acid solution in benzene in dropped on a water surface...
Solution:
Given data:
Concentration of acid solution, C = 0.016 M
Area to be covered, A = 500 cm²
Area covered by a single acid molecule, a = 0.2 nm²
Conversion of units:
1 nm = 10⁻⁹ m
1 cm² = 10⁻⁴ m²
So, the area covered by a single acid molecule in m² will be:
a = 0.2 × 10⁻⁹ m² = 2 × 10⁻¹¹ m²
To calculate the volume of the solution required to cover the given area, we need to find the number of acid molecules required to form a monolayer on the water surface.
The number of acid molecules required can be calculated as:
N = A/a
where N is the number of acid molecules required and A is the area to be covered.
Substituting the given values, we get:
N = (500 × 10⁻⁴ m²) / (2 × 10⁻¹¹ m²) = 2.5 × 10¹⁵
Now, we can calculate the volume of the solution required as:
V = N × Vm
where V is the volume of the solution required and Vm is the molar volume of the solution.
Vm can be calculated as:
Vm = (RT) / P
where R is the gas constant, T is the temperature, and P is the pressure.
Assuming the temperature and pressure to be constant, we can take Vm as a constant value.
Substituting the given values, we get:
Vm = (0.0821 × 298) / 1 = 24.51 L/mol
Now, we can calculate the volume of the solution required as:
V = N × Vm / C
Substituting the given values, we get:
V = (2.5 × 10¹⁵) × (24.51 × 10⁻³) / 0.016 = 3.83 × 10¹² L
Therefore, the volume of the above solution required to cover a 500 cm square surface area of water with a monomolecular layer of acid is 3.83 × 10¹² L.
Explanation:
To form a monomolecular layer, the acid molecules need to spread evenly on the water surface without any overlap or gap. The area covered by a single acid molecule is known, so we can calculate the number of acid molecules required to cover the given area. Once we know the number of acid molecules required, we can calculate the volume of the solution required using the molar volume of the solution.
Given data:
Concentration of acid solution, C = 0.016 M
Area to be covered, A = 500 cm²
Area covered by a single acid molecule, a = 0.2 nm²
Conversion of units:
1 nm = 10⁻⁹ m
1 cm² = 10⁻⁴ m²
So, the area covered by a single acid molecule in m² will be:
a = 0.2 × 10⁻⁹ m² = 2 × 10⁻¹¹ m²
To calculate the volume of the solution required to cover the given area, we need to find the number of acid molecules required to form a monolayer on the water surface.
The number of acid molecules required can be calculated as:
N = A/a
where N is the number of acid molecules required and A is the area to be covered.
Substituting the given values, we get:
N = (500 × 10⁻⁴ m²) / (2 × 10⁻¹¹ m²) = 2.5 × 10¹⁵
Now, we can calculate the volume of the solution required as:
V = N × Vm
where V is the volume of the solution required and Vm is the molar volume of the solution.
Vm can be calculated as:
Vm = (RT) / P
where R is the gas constant, T is the temperature, and P is the pressure.
Assuming the temperature and pressure to be constant, we can take Vm as a constant value.
Substituting the given values, we get:
Vm = (0.0821 × 298) / 1 = 24.51 L/mol
Now, we can calculate the volume of the solution required as:
V = N × Vm / C
Substituting the given values, we get:
V = (2.5 × 10¹⁵) × (24.51 × 10⁻³) / 0.016 = 3.83 × 10¹² L
Therefore, the volume of the above solution required to cover a 500 cm square surface area of water with a monomolecular layer of acid is 3.83 × 10¹² L.
Explanation:
To form a monomolecular layer, the acid molecules need to spread evenly on the water surface without any overlap or gap. The area covered by a single acid molecule is known, so we can calculate the number of acid molecules required to cover the given area. Once we know the number of acid molecules required, we can calculate the volume of the solution required using the molar volume of the solution.
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A 0.016 M of an acid solution in benzene in dropped on a water surface , the benzene evaporates and the acid form a monomolecular flim of solid type . What volume of the above solution would be required to cover a 500 cm square surface area of water with a monomolecular layer of acid . The area covered by a single acid molecule is 0.2 nm?
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A 0.016 M of an acid solution in benzene in dropped on a water surface , the benzene evaporates and the acid form a monomolecular flim of solid type . What volume of the above solution would be required to cover a 500 cm square surface area of water with a monomolecular layer of acid . The area covered by a single acid molecule is 0.2 nm? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A 0.016 M of an acid solution in benzene in dropped on a water surface , the benzene evaporates and the acid form a monomolecular flim of solid type . What volume of the above solution would be required to cover a 500 cm square surface area of water with a monomolecular layer of acid . The area covered by a single acid molecule is 0.2 nm? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 0.016 M of an acid solution in benzene in dropped on a water surface , the benzene evaporates and the acid form a monomolecular flim of solid type . What volume of the above solution would be required to cover a 500 cm square surface area of water with a monomolecular layer of acid . The area covered by a single acid molecule is 0.2 nm?.
A 0.016 M of an acid solution in benzene in dropped on a water surface , the benzene evaporates and the acid form a monomolecular flim of solid type . What volume of the above solution would be required to cover a 500 cm square surface area of water with a monomolecular layer of acid . The area covered by a single acid molecule is 0.2 nm? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A 0.016 M of an acid solution in benzene in dropped on a water surface , the benzene evaporates and the acid form a monomolecular flim of solid type . What volume of the above solution would be required to cover a 500 cm square surface area of water with a monomolecular layer of acid . The area covered by a single acid molecule is 0.2 nm? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 0.016 M of an acid solution in benzene in dropped on a water surface , the benzene evaporates and the acid form a monomolecular flim of solid type . What volume of the above solution would be required to cover a 500 cm square surface area of water with a monomolecular layer of acid . The area covered by a single acid molecule is 0.2 nm?.
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