6 gram of steam at 100 degree c is mixed with 6 gram of ice at 0degree...
Given information:
Mass of steam = 6 grams
Temperature of steam = 100°C
Mass of ice = 6 grams
Temperature of ice = 0°C
Calculating the heat absorbed by the steam:
The heat absorbed by a substance can be calculated using the formula: Q = mcΔT, where Q is the heat absorbed, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
For steam, the specific heat capacity (c) is approximately 2.03 J/g°C.
Q(steam) = 6 g * 2.03 J/g°C * (100°C - 0°C)
Q(steam) = 1218 J
Calculating the heat released by the ice:
The heat released by the ice can also be calculated using the same formula.
For ice, the specific heat capacity (c) is approximately 2.09 J/g°C.
Q(ice) = 6 g * 2.09 J/g°C * (0°C - (-100°C))
Q(ice) = 1254 J
Calculating the heat required for phase change:
To convert ice at 0°C to water at 0°C, we need to calculate the heat required for the phase change. The heat required for phase change can be calculated using the formula: Q = mL, where Q is the heat required, m is the mass of the substance, and L is the latent heat of fusion.
For ice, the latent heat of fusion (L) is approximately 334 J/g.
Q(phase change) = 6 g * 334 J/g
Q(phase change) = 2004 J
Total heat absorbed:
The total heat absorbed by the system is the sum of the heat absorbed by the steam, the heat released by the ice, and the heat required for the phase change.
Total heat absorbed = Q(steam) + Q(ice) + Q(phase change)
Total heat absorbed = 1218 J + 1254 J + 2004 J
Total heat absorbed = 4476 J
Calculating the mass of uncondensed steam:
The heat absorbed by the steam is equal to the heat released by the ice and the heat required for the phase change. Since the heat absorbed is the same as the heat released and the heat required for phase change, it implies that all the steam has condensed into water.
Therefore, the mass of uncondensed steam is 0 grams.
Conclusion:
The mass of uncondensed steam is 0 grams.