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PH of mixture of 500 ml 0.1 molar ch3cooh and 250 ml of 0.1 molar naoh solution is?
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PH of mixture of 500 ml 0.1 molar ch3cooh and 250 ml of 0.1 molar naoh...
Calculation of pH of Mixture of CH3COOH and NaOH Solution
1. Balanced chemical equation
2. Moles of CH3COOH and NaOH
3. Limiting reagent and excess reagent
4. Concentration of resulting salt
5. pH of the solution
pKa = 4
The pH of a mixture of CH3COOH and NaOH solution can be calculated using the following steps:
- Write the balanced chemical equation for the reaction between CH3COOH and NaOH.
- Determine the moles of CH3COOH and NaOH in the solution.
- Identify the limiting reagent and calculate the amount of excess reagent remaining.
- Calculate the concentration of the resulting salt.
- Use the concentration of the salt to calculate the pH of the solution.
1. Balanced chemical equation
The balanced chemical equation for the reaction between CH3COOH and NaOH is:
CH3COOH + NaOH → CH3COONa + H2O
2. Moles of CH3COOH and NaOH
The moles of CH3COOH and NaOH in the solution can be calculated using the formula:
moles = concentration × volume
For CH3COOH:
moles CH3COOH = 0.1 mol/L × 0.5 L = 0.05 mol
For NaOH:
moles NaOH = 0.1 mol/L × 0.25 L = 0.025 mol
3. Limiting reagent and excess reagent
The limiting reagent is the reactant that is completely consumed in the reaction. In this case, NaOH is the limiting reagent because it has fewer moles than CH3COOH. The excess reagent is the reactant that remains after the limiting reagent is completely consumed. In this case, CH3COOH is the excess reagent.
The amount of excess CH3COOH remaining can be calculated using the formula:
moles of excess CH3COOH = moles CH3COOH - moles NaOH
moles of excess CH3COOH = 0.05 mol - 0.025 mol = 0.025 mol
4. Concentration of resulting salt
The concentration of the resulting salt, CH3COONa, can be calculated using the formula:
concentration of CH3COONa = moles of CH3COONa / total volume of solution
moles of CH3COONa = moles NaOH = 0.025 mol
total volume of solution = 0.5 L + 0.25 L = 0.75 L
concentration of CH3COONa = 0.025 mol / 0.75 L = 0.033 mol/L
5. pH of the solution
The pH of the solution can be calculated using the formula:
pH = pKa + log([A-] / [HA])
where:
pKa = 4
Community Answer
PH of mixture of 500 ml 0.1 molar ch3cooh and 250 ml of 0.1 molar naoh...
Here the H+ ions will be produced only by weak acid (CH3COOH)....
CH3COOH>>>>> CH3COO- + H+
0.1M. 0.1M. 0.1M
PH= -log [H+]
PH=-log(0.1)
PH=1
CH3COOH>>>>> CH3COO- + H+
0.1M. 0.1M. 0.1M
PH= -log [H+]
PH=-log(0.1)
PH=1
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PH of mixture of 500 ml 0.1 molar ch3cooh and 250 ml of 0.1 molar naoh solution is?
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PH of mixture of 500 ml 0.1 molar ch3cooh and 250 ml of 0.1 molar naoh solution is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about PH of mixture of 500 ml 0.1 molar ch3cooh and 250 ml of 0.1 molar naoh solution is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for PH of mixture of 500 ml 0.1 molar ch3cooh and 250 ml of 0.1 molar naoh solution is?.
PH of mixture of 500 ml 0.1 molar ch3cooh and 250 ml of 0.1 molar naoh solution is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about PH of mixture of 500 ml 0.1 molar ch3cooh and 250 ml of 0.1 molar naoh solution is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for PH of mixture of 500 ml 0.1 molar ch3cooh and 250 ml of 0.1 molar naoh solution is?.
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