If cos A + cos2 A = 1 and a sin12 A + b sin10 A + c sin8 A + d sin6 A ...
Correct Answer :- B
Explanation : Cos A = 1 - Cos2A
=> Cos A = Sin2A
=> Cos2A = Sin4A
=> 1 – Sin2A = Sin4A
=> 1 = Sin44A + Sin2A
=> 13 = (Sin4A + Sin2A)3
=> 1 = Sin12 A + Sin6A + 3Sin8A + 3Sin10A
=> Sin12A + Sin6A + 3Sin8A + 3Sin10A – 1 = 0
On comparing,
a = 1, b = 3 , c = 3 , d = 1
= a+b/c+d
Hence, the answer is 1
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If cos A + cos2 A = 1 and a sin12 A + b sin10 A + c sin8 A + d sin6 A ...
To solve this problem, we need to use trigonometric identities and equations. Let's break down the steps to find the value of a b / c d:
Given equations:
1) cos A cos2 A = 1
2) a sin12 A b sin10 A c sin8 A d sin6 A - 1 = 0
Step 1: Simplifying the first equation
Using the identity cos2 A = 1 - sin2 A, we can rewrite the first equation as:
cos A (1 - sin2 A) = 1
cos A - cos A sin2 A = 1
cos A = 1 + cos A sin2 A
Step 2: Simplifying the second equation
Let's rewrite the second equation in terms of sin A using the identity sin2 A = 1 - cos2 A:
a sin12 A - b sin10 A + c sin8 A - d sin6 A = 1
Step 3: Using the double angle identity
Using the double angle identity sin 2A = 2sin A cos A, we can rewrite the first equation as:
cos A = 1 + 2sin A cos A sin2 A
cos A = 1 + 2sin A cos A (1 - cos2 A)
cos A = 1 + 2sin A cos A - 2sin A cos3 A
Step 4: Simplifying the equation system
Now, let's substitute the value of cos A from the first equation into the second equation:
a sin12 A - b sin10 A + c sin8 A - d sin6 A = 1 + 2sin A cos A - 2sin A cos3 A
Step 5: Rearranging the equation
Rearranging the equation, we get:
2sin A cos A - 2sin A cos3 A + a sin12 A - b sin10 A + c sin8 A - d sin6 A - 1 = 0
Step 6: Comparing coefficients
Comparing the coefficients of sin A and cos A in the equation, we have:
2cos A = a
-2cos3 A - b = 0
1 = c
-1 = d
Step 7: Finding the value of a b / c d
Now, we can calculate the value of a b / c d:
a = 2cos A = 2(1) = 2
b = -2cos3 A = -2(1)3 = -2
c = 1
d = -1
Therefore, a b / c d = (2)(-2) / (1)(-1) = 4 / 1 = 4
Hence, the correct answer is option 'B' (4).