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A truck travelling with uniform acceleration crosses two points A and B with velocities 60m/s and 40m/s respectively.The speed of the body at the midpoint of A and B is nearest to:?
Most Upvoted Answer
A truck travelling with uniform acceleration crosses two points A and ...
Explanation:

  • Let us consider the velocity of the truck at point A as u = 60 m/s and the velocity of the truck at point B as v = 40 m/s.

  • Let the distance between points A and B be d.

  • Let the speed of the truck at the midpoint of A and B be v1.

  • Using the formula v^2 - u^2 = 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance travelled, we can find the acceleration of the truck.

  • Substituting the values, we get a = -1000/d.

  • Using the formula v1^2 = u^2 + 2ad, we can find the speed of the truck at the midpoint of A and B.

  • Substituting the values, we get v1^2 = (60)^2 + 2(-1000/d)(d/2) = 3600 - 1000 = 2600.

  • Taking the square root of both sides, we get v1 = 50.99 m/s.

  • Therefore, the speed of the truck at the midpoint of A and B is nearest to 51 m/s.

Community Answer
A truck travelling with uniform acceleration crosses two points A and ...
50 m/s
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A truck travelling with uniform acceleration crosses two points A and B with velocities 60m/s and 40m/s respectively.The speed of the body at the midpoint of A and B is nearest to:?
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