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When excess of aqueous KCN soon is added to an aqueous soln of CuSO4, the complex [Cu(CN) 4]-2 is formed. On passing H2S gas through this soln no precipitate is formed because (a) sulphide ion cannot replace CN- ion (b) [Cu(CN) 4]2- does not give Cu2 ion in soln (c) sulphide ion from H2S do not form complexes (d) sulphide ions cannot replace sulphate ions from CuSO4 soln Correct opt :(b). Can any one explain briefly pls? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared
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When excess of aqueous KCN soon is added to an aqueous soln of CuSO4, the complex [Cu(CN) 4]-2 is formed. On passing H2S gas through this soln no precipitate is formed because (a) sulphide ion cannot replace CN- ion (b) [Cu(CN) 4]2- does not give Cu2 ion in soln (c) sulphide ion from H2S do not form complexes (d) sulphide ions cannot replace sulphate ions from CuSO4 soln Correct opt :(b). Can any one explain briefly pls?, a detailed solution for When excess of aqueous KCN soon is added to an aqueous soln of CuSO4, the complex [Cu(CN) 4]-2 is formed. On passing H2S gas through this soln no precipitate is formed because (a) sulphide ion cannot replace CN- ion (b) [Cu(CN) 4]2- does not give Cu2 ion in soln (c) sulphide ion from H2S do not form complexes (d) sulphide ions cannot replace sulphate ions from CuSO4 soln Correct opt :(b). Can any one explain briefly pls? has been provided alongside types of When excess of aqueous KCN soon is added to an aqueous soln of CuSO4, the complex [Cu(CN) 4]-2 is formed. On passing H2S gas through this soln no precipitate is formed because (a) sulphide ion cannot replace CN- ion (b) [Cu(CN) 4]2- does not give Cu2 ion in soln (c) sulphide ion from H2S do not form complexes (d) sulphide ions cannot replace sulphate ions from CuSO4 soln Correct opt :(b). Can any one explain briefly pls? theory, EduRev gives you an
ample number of questions to practice When excess of aqueous KCN soon is added to an aqueous soln of CuSO4, the complex [Cu(CN) 4]-2 is formed. On passing H2S gas through this soln no precipitate is formed because (a) sulphide ion cannot replace CN- ion (b) [Cu(CN) 4]2- does not give Cu2 ion in soln (c) sulphide ion from H2S do not form complexes (d) sulphide ions cannot replace sulphate ions from CuSO4 soln Correct opt :(b). Can any one explain briefly pls? tests, examples and also practice NEET tests.