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What is the maximum concentration of equimolar solution of ferrous sulphate and sodium sulphide, so that when mixed in equal volumes there is no precipitation of iron sulphide? [Ksp for iron sulphide = 6.3 
×
 10-18]
  • a)
    ×
     10-9 mol L-1
  • b)
    4.8 
    ×
     10-11 mol L-1
  • c)
    5.02 
    ×
     10-9 mol L-1
  • d)
    ×
     10-9 mol L-1
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
What is the maximum concentration of equimolar solution of ferrous sul...
Let the concentration of FeSO4 and Na2S be x mol L-1.
Then, after mixing equal volumes:
[FeSO4] = [Na2S] = x/2 M
Or 
[Fe2+] = [S2-] = x/2 M
FeS ⇌ Fe2+ + S2-
Ksp = [Fe2+][S2-]
6.3 
×
 10-18 = (x/2)(x/2)
On solving, x = 5.02 
×
 10-9 mol L-1
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Most Upvoted Answer
What is the maximum concentration of equimolar solution of ferrous sul...
To find the maximum concentration of equimolar solutions of ferrous sulphate (FeSO4) and sodium sulphide (Na2S) that can be mixed without precipitation of iron sulphide (FeS), we need to consider the solubility product constant (Ksp) of iron sulphide.

The balanced chemical equation for the precipitation reaction is:

FeSO4 + Na2S -> FeS + Na2SO4

The Ksp expression for iron sulphide is:

Ksp = [Fe2+][S2-]

Since the solutions are equimolar, the concentrations of Fe2+ and S2- ions in the mixed solution will be the same. Let's denote this concentration as x.

Therefore, the Ksp expression becomes:

Ksp = x * x = x^2

Given that Ksp for iron sulphide is 6.3 x 10^-19, we can solve for x:

x^2 = 6.3 x 10^-19
x = sqrt(6.3 x 10^-19)
x = 7.94 x 10^-10 M

Since the concentrations of Fe2+ and S2- ions are the same in the equimolar solutions, the maximum concentration of each of the solutions that can be mixed without precipitation is 7.94 x 10^-10 M.
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What is the maximum concentration of equimolar solution of ferrous sulphate and sodium sulphide, so that when mixed in equal volumes there is no precipitation of iron sulphide? [Kspfor iron sulphide = 6.3×10-18]a)4×10-9mol L-1b)4.8×10-11mol L-1c)5.02×10-9mol L-1d)6×10-9mol L-1Correct answer is option 'C'. Can you explain this answer?
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