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0.7g of iron reacts directly with 0.4g of sulphur to form ferrous sulphide. If 2.8g of iron dissolves in dil. HCL and excess of sodium sulphide solution is added, 4.4g of iron sulphide is precipitated. If it obeys the law of constant composition. What is the ratio of weights of Fe:S? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared
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0.7g of iron reacts directly with 0.4g of sulphur to form ferrous sulphide. If 2.8g of iron dissolves in dil. HCL and excess of sodium sulphide solution is added, 4.4g of iron sulphide is precipitated. If it obeys the law of constant composition. What is the ratio of weights of Fe:S?, a detailed solution for 0.7g of iron reacts directly with 0.4g of sulphur to form ferrous sulphide. If 2.8g of iron dissolves in dil. HCL and excess of sodium sulphide solution is added, 4.4g of iron sulphide is precipitated. If it obeys the law of constant composition. What is the ratio of weights of Fe:S? has been provided alongside types of 0.7g of iron reacts directly with 0.4g of sulphur to form ferrous sulphide. If 2.8g of iron dissolves in dil. HCL and excess of sodium sulphide solution is added, 4.4g of iron sulphide is precipitated. If it obeys the law of constant composition. What is the ratio of weights of Fe:S? theory, EduRev gives you an
ample number of questions to practice 0.7g of iron reacts directly with 0.4g of sulphur to form ferrous sulphide. If 2.8g of iron dissolves in dil. HCL and excess of sodium sulphide solution is added, 4.4g of iron sulphide is precipitated. If it obeys the law of constant composition. What is the ratio of weights of Fe:S? tests, examples and also practice NEET tests.