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In a double-pipe counter flow heat exchanger 1000kh/h, oil having a specific heat 20 j/kg -K is cooled from 150oC to 125oC by 1250 kg/h of fluid having specific heat 16j/kg-K. The cold fluid leaves the heat exchanger at 75oC . In this case, the temperature at which the cooling fluid enters the heat exchanger and LMTD are __________
- a)25o C and 50oC
- b)50o C and 50oC
- c)50o C and 75oC
- d)75o C and 50oC
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
In a double-pipe counter flow heat exchanger 1000kh/h, oil having a s...
x = 0 x x = l
mhcph = 1000 x 20 = 20,000j/hr-K
mccph = 1200 x 16 = 20,000j/hr-K
mhcph = mccph
Hence for a balanced Counter flow heat exchangers
ΔTm = ΔTi =ΔTe
∴ ΔTm = 150 -75 - 75oC
Thi - Tce = The - Tci
Tci - The = Tce - Thi
Tci = 50oC
Most Upvoted Answer
In a double-pipe counter flow heat exchanger 1000kh/h, oil having a s...
Solution:
Given,
Flow rate of oil (m1) = 1000 kg/h
Specific heat of oil (cp1) = 20 J/kg-K
Initial temperature of oil (T1) = 150°C
Final temperature of oil (T2) = 125°C
Flow rate of cooling fluid (m2) = 1250 kg/h
Specific heat of cooling fluid (cp2) = 16 J/kg-K
Temperature of cooling fluid after heat exchange (T2') = 75°C
We need to find out the temperature of cooling fluid before heat exchange (T1') and the LMTD.
Calculation:
From the energy balance equation,
m1 cp1 (T1 - T2) = m2 cp2 (T2' - T1')
Substituting the values, we get
1000 x 20 x (150 - 125) = 1250 x 16 x (75 - T1')
Simplifying the above equation, we get
T1' = 50°C
Now, we can calculate the LMTD as
LMTD = (ΔT1 - ΔT2)/ln(ΔT1/ΔT2)
Where,
ΔT1 = T1 - T2' = 150 - 75 = 75°C
ΔT2 = T1' - T2 = 50 - 125 = -75°C
Substituting the values, we get
LMTD = (75 - (-75))/ln(75/(-75)) = 50°C
Therefore, the temperature at which the cooling fluid enters the heat exchanger is 50°C and the LMTD is 50°C. Hence, the correct answer is option C.
Given,
Flow rate of oil (m1) = 1000 kg/h
Specific heat of oil (cp1) = 20 J/kg-K
Initial temperature of oil (T1) = 150°C
Final temperature of oil (T2) = 125°C
Flow rate of cooling fluid (m2) = 1250 kg/h
Specific heat of cooling fluid (cp2) = 16 J/kg-K
Temperature of cooling fluid after heat exchange (T2') = 75°C
We need to find out the temperature of cooling fluid before heat exchange (T1') and the LMTD.
Calculation:
From the energy balance equation,
m1 cp1 (T1 - T2) = m2 cp2 (T2' - T1')
Substituting the values, we get
1000 x 20 x (150 - 125) = 1250 x 16 x (75 - T1')
Simplifying the above equation, we get
T1' = 50°C
Now, we can calculate the LMTD as
LMTD = (ΔT1 - ΔT2)/ln(ΔT1/ΔT2)
Where,
ΔT1 = T1 - T2' = 150 - 75 = 75°C
ΔT2 = T1' - T2 = 50 - 125 = -75°C
Substituting the values, we get
LMTD = (75 - (-75))/ln(75/(-75)) = 50°C
Therefore, the temperature at which the cooling fluid enters the heat exchanger is 50°C and the LMTD is 50°C. Hence, the correct answer is option C.
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In a double-pipe counter flow heat exchanger 1000kh/h, oil having a specific heat 20 j/kg -K is cooled from 150oC to 125oC by 1250 kg/h of fluid having specific heat 16j/kg-K. The cold fluid leaves the heat exchanger at 75oC . In this case, the temperature at which the cooling fluid enters the heat exchanger and LMTD are __________a) 25o C and 50oCb) 50o C and 50oCc) 50o C and 75oCd) 75o C and 50oCCorrect answer is option 'C'. Can you explain this answer?
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In a double-pipe counter flow heat exchanger 1000kh/h, oil having a specific heat 20 j/kg -K is cooled from 150oC to 125oC by 1250 kg/h of fluid having specific heat 16j/kg-K. The cold fluid leaves the heat exchanger at 75oC . In this case, the temperature at which the cooling fluid enters the heat exchanger and LMTD are __________a) 25o C and 50oCb) 50o C and 50oCc) 50o C and 75oCd) 75o C and 50oCCorrect answer is option 'C'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about In a double-pipe counter flow heat exchanger 1000kh/h, oil having a specific heat 20 j/kg -K is cooled from 150oC to 125oC by 1250 kg/h of fluid having specific heat 16j/kg-K. The cold fluid leaves the heat exchanger at 75oC . In this case, the temperature at which the cooling fluid enters the heat exchanger and LMTD are __________a) 25o C and 50oCb) 50o C and 50oCc) 50o C and 75oCd) 75o C and 50oCCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a double-pipe counter flow heat exchanger 1000kh/h, oil having a specific heat 20 j/kg -K is cooled from 150oC to 125oC by 1250 kg/h of fluid having specific heat 16j/kg-K. The cold fluid leaves the heat exchanger at 75oC . In this case, the temperature at which the cooling fluid enters the heat exchanger and LMTD are __________a) 25o C and 50oCb) 50o C and 50oCc) 50o C and 75oCd) 75o C and 50oCCorrect answer is option 'C'. Can you explain this answer?.
Solutions for In a double-pipe counter flow heat exchanger 1000kh/h, oil having a specific heat 20 j/kg -K is cooled from 150oC to 125oC by 1250 kg/h of fluid having specific heat 16j/kg-K. The cold fluid leaves the heat exchanger at 75oC . In this case, the temperature at which the cooling fluid enters the heat exchanger and LMTD are __________a) 25o C and 50oCb) 50o C and 50oCc) 50o C and 75oCd) 75o C and 50oCCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemical Engineering.
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