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A strain gauge is attached to a bar of length 20 cm, which is subjected to a tensile force. The nominal resistance of the strain gauge is 100Ω. The changes in resistance and elongation in the bar measured are 0.35Ω and 0.2 mm, respectively. The gauge factor of the strain gauge is (2001)
  • a)
    2
  • b)
    3.5
  • c)
    10
  • d)
    100
Correct answer is option 'B'. Can you explain this answer?
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A strain gauge is attached to a bar of length 20 cm, which is subject...
Given data:
Length of the bar (L) = 20 cm = 0.2 m
Nominal resistance of the strain gauge (R0) = 100 Ω
Change in resistance (ΔR) = 0.35 Ω
Elongation in the bar (ΔL) = 0.2 mm = 0.2 × 10^-3 m

To find:
Gauge factor (GF) of the strain gauge

Solution:
The gauge factor (GF) is defined as the ratio of the change in resistance (ΔR) to the original resistance (R0) multiplied by the ratio of the change in length (ΔL) to the original length (L).

The formula for the gauge factor is given by:
GF = (ΔR / R0) / (ΔL / L)

Substituting the given values:
GF = (0.35 / 100) / (0.2 × 10^-3 / 0.2)

Simplifying the above expression:
GF = (0.35 / 100) / (10^-3 / 0.2)
GF = (0.35 × 0.2) / (100 × 10^-3)
GF = 0.07 / 0.01
GF = 7

Therefore, the gauge factor of the strain gauge is 7.

Conclusion:
The gauge factor of the strain gauge is 7, which corresponds to option B.
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A strain gauge is attached to a bar of length 20 cm, which is subjected to a tensile force. The nominal resistance of the strain gauge is 100Ω. The changes in resistance and elongation in the bar measured are 0.35Ω and 0.2 mm, respectively. The gauge factor of the strain gauge is (2001)a)2b)3.5c)10d)100Correct answer is option 'B'. Can you explain this answer?
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