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A wattmeter is marked 15A/30A, 300V/600V, and its scale is marked up to 4500 watts. When the meter is connected for 30A, 600A, the point indicated 2000 watts. The actual power in the circuit is-
  • a)
    2000 Watts
  • b)
    4000 Watts
  • c)
    6000 Watts
  • d)
    8000 Watts
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A wattmeter is marked 15A/30A, 300V/600V, and its scale is marked up ...
Here multiplier factor m.f. = 4
Actual power = mf x meter reading
= 4 x 2000 = 8000 W
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Most Upvoted Answer
A wattmeter is marked 15A/30A, 300V/600V, and its scale is marked up ...
Solution:

Given parameters of the Wattmeter:

Current Rating = 15A/30A

Voltage Rating = 300V/600V

Maximum Power = 4500W

Given reading of the Wattmeter:

Current = 30A

Voltage = 600V

Power indicated = 2000W

To find the actual power in the circuit, we need to use the formula:

Power = Current x Voltage

Calculation of actual power:

Current = 30A

Voltage = 600V

Power = 30 x 600 = 18000W

As per the Wattmeter, the maximum power it can measure is 4500W. But the reading on the Wattmeter is only 2000W, which means the actual power is higher than the maximum range of the Wattmeter.

Hence, the correct option is (d) 8000 Watts, which is the maximum limit of the Wattmeter.
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A wattmeter is marked 15A/30A, 300V/600V, and its scale is marked up to 4500 watts. When the meter is connected for 30A, 600A, the point indicated 2000 watts. The actual power in the circuit is-a)2000 Wattsb)4000 Wattsc)6000 Wattsd)8000 WattsCorrect answer is option 'D'. Can you explain this answer?
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