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A 4-pole generator is running at 1200 rpm—the frequency and time period of the emf generated in its coils, respectively.
- a)50 Hz, 0.02 sec
- b)40 Hz, 0.025 sec
- c)300 Hz, 0.00333 sec
- d)2400 Hz, (1/2400sec)
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A 4-pole generator is running at 1200 rpm—the frequency and time peri...
N = 120f/P
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1200 = 120 x f/4
f = 1200 x 4/120
T = I/f = 1/40
Most Upvoted Answer
A 4-pole generator is running at 1200 rpm—the frequency and time peri...
Given: A 4-pole generator running at 1200 rpm
To find: Frequency and time period of the emf generated in its coils
Formula:
Frequency (f) = (N × P)/120 where N is the speed of the generator in rpm and P is the number of poles in the generator.
Time period (T) = 1/f
Calculation:
Number of poles (P) = 4
Speed of the generator (N) = 1200 rpm
Frequency (f) = (N × P)/120 = (1200 × 4)/120 = 40 Hz
Time period (T) = 1/f = 1/40 = 0.025 sec
Therefore, the correct answer is option B) 40 Hz, 0.025 sec.
To find: Frequency and time period of the emf generated in its coils
Formula:
Frequency (f) = (N × P)/120 where N is the speed of the generator in rpm and P is the number of poles in the generator.
Time period (T) = 1/f
Calculation:
Number of poles (P) = 4
Speed of the generator (N) = 1200 rpm
Frequency (f) = (N × P)/120 = (1200 × 4)/120 = 40 Hz
Time period (T) = 1/f = 1/40 = 0.025 sec
Therefore, the correct answer is option B) 40 Hz, 0.025 sec.
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A 4-pole generator is running at 1200 rpm—the frequency and time period of the emf generated in its coils, respectively.a)50 Hz, 0.02 secb)40 Hz, 0.025 secc)300 Hz, 0.00333 secd)2400 Hz, (1/2400sec)Correct answer is option 'B'. Can you explain this answer?
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