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The positive negative and zero sequence impedances of the 3-phase synchronous generator are j 0.5 pu, j 0.3 pu and j 0.2 pu, respectively. When a symmetrical fault occurs on the machine terminals. Find the fault current. The generator neutral is grounded through reactance of j0.1 pu-
  • a)
    (-j33.33pu)
  • b)
    (-j1.67pu)
  • c)
    (-j2.0pu)
  • d)
    (-j2.5pu)
Correct answer is option 'B'. Can you explain this answer?
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The positive negative and zero sequence impedances of the 3-phase syn...
For symmetrical fault,
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The positive negative and zero sequence impedances of the 3-phase syn...
Given:
Positive sequence impedance (Z1) = j0.5 pu
Negative sequence impedance (Z2) = j0.3 pu
Zero sequence impedance (Z0) = j0.2 pu
Reactance of generator neutral grounding (Xn) = j0.1 pu

To Find:
Fault current

Explanation:
The fault current can be calculated using the following formula:

If = (Va - Vf) / (Z1 + Z2 + Z0 + 3*Xn)

Where:
If = Fault current
Va = Generator terminal voltage
Vf = Fault voltage

Since it is mentioned that a symmetrical fault occurs on the machine terminals, the fault voltage (Vf) will be equal to the generator terminal voltage (Va).

Substituting the given values:
Va = Vf

If = (Va - Va) / (Z1 + Z2 + Z0 + 3*Xn)
= 0 / (Z1 + Z2 + Z0 + 3*Xn)
= 0 / (j0.5 + j0.3 + j0.2 + 3*j0.1)
= 0 / (j0.5 + j0.3 + j0.2 + j0.3)
= 0 / (j1 + j0.5)
= 0 / j1.5
= 0

Therefore, the fault current is 0.

Conclusion:
The fault current in the given scenario is 0.
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The positive negative and zero sequence impedances of the 3-phase synchronous generator are j 0.5 pu, j 0.3 pu and j 0.2 pu, respectively. When a symmetrical fault occurs on the machine terminals. Find the fault current. The generator neutral is grounded through reactance of j0.1 pu-a)(-j33.33pu)b)(-j1.67pu)c)(-j2.0pu)d)(-j2.5pu)Correct answer is option 'B'. Can you explain this answer?
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