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A 50 kVA, 500 V, single phase a.c. generator gave the following test results:
Open circuit test: A field current of 12 A produced an e.m.f. of 300 V.
Short circuit test: A field current of 12 A caused a current of 175 A to flow in the short-circuited armature.
The synchronous impedance of the generator is
Open circuit test: A field current of 12 A produced an e.m.f. of 300 V.
Short circuit test: A field current of 12 A caused a current of 175 A to flow in the short-circuited armature.
The synchronous impedance of the generator is
- a)2.61 Ω
- b)3.84 Ω
- c)4.85 Ω
- d)1.71 Ω
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A 50 kVA, 500 V, single phase a.c. generator gave the following test r...
Synchronous impedance,
Zs = 300/175 = 1.71 Ω
Zs = 300/175 = 1.71 Ω
Most Upvoted Answer
A 50 kVA, 500 V, single phase a.c. generator gave the following test r...
To find the synchronous impedance of the generator, we will use the open circuit test and the short circuit test.
In the open circuit test, the field current is 12A and the voltage is 300V. The open circuit voltage is given by the formula:
E_oc = (V + jI_oc * Z_s)
where:
E_oc is the open circuit voltage
V is the voltage
I_oc is the open circuit current
Z_s is the synchronous impedance
Since the open circuit current is zero, the equation simplifies to:
E_oc = V
Therefore, the open circuit voltage is equal to the voltage, which is 300V.
In the short circuit test, the field current is 12A and the current is 175A. The short circuit current is given by the formula:
I_sc = (V / Z_s)
where:
I_sc is the short circuit current
V is the voltage
Z_s is the synchronous impedance
Rearranging the equation, we have:
Z_s = V / I_sc
Plugging in the values, we get:
Z_s = 300V / 175A
Z_s = 1.714 ohms
Therefore, the synchronous impedance of the generator is approximately 1.71 ohms.
In the open circuit test, the field current is 12A and the voltage is 300V. The open circuit voltage is given by the formula:
E_oc = (V + jI_oc * Z_s)
where:
E_oc is the open circuit voltage
V is the voltage
I_oc is the open circuit current
Z_s is the synchronous impedance
Since the open circuit current is zero, the equation simplifies to:
E_oc = V
Therefore, the open circuit voltage is equal to the voltage, which is 300V.
In the short circuit test, the field current is 12A and the current is 175A. The short circuit current is given by the formula:
I_sc = (V / Z_s)
where:
I_sc is the short circuit current
V is the voltage
Z_s is the synchronous impedance
Rearranging the equation, we have:
Z_s = V / I_sc
Plugging in the values, we get:
Z_s = 300V / 175A
Z_s = 1.714 ohms
Therefore, the synchronous impedance of the generator is approximately 1.71 ohms.
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A 50 kVA, 500 V, single phase a.c. generator gave the following test results:Open circuit test: A field current of 12 A produced an e.m.f. of 300 V.Short circuit test: A field current of 12 A caused a current of 175 A to flow in the short-circuited armature.The synchronous impedance of the generator isa)2.61Ωb)3.84Ωc)4.85Ωd)1.71ΩCorrect answer is option 'D'. Can you explain this answer?
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A 50 kVA, 500 V, single phase a.c. generator gave the following test results:Open circuit test: A field current of 12 A produced an e.m.f. of 300 V.Short circuit test: A field current of 12 A caused a current of 175 A to flow in the short-circuited armature.The synchronous impedance of the generator isa)2.61Ωb)3.84Ωc)4.85Ωd)1.71ΩCorrect answer is option 'D'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about A 50 kVA, 500 V, single phase a.c. generator gave the following test results:Open circuit test: A field current of 12 A produced an e.m.f. of 300 V.Short circuit test: A field current of 12 A caused a current of 175 A to flow in the short-circuited armature.The synchronous impedance of the generator isa)2.61Ωb)3.84Ωc)4.85Ωd)1.71ΩCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 50 kVA, 500 V, single phase a.c. generator gave the following test results:Open circuit test: A field current of 12 A produced an e.m.f. of 300 V.Short circuit test: A field current of 12 A caused a current of 175 A to flow in the short-circuited armature.The synchronous impedance of the generator isa)2.61Ωb)3.84Ωc)4.85Ωd)1.71ΩCorrect answer is option 'D'. Can you explain this answer?.
A 50 kVA, 500 V, single phase a.c. generator gave the following test results:Open circuit test: A field current of 12 A produced an e.m.f. of 300 V.Short circuit test: A field current of 12 A caused a current of 175 A to flow in the short-circuited armature.The synchronous impedance of the generator isa)2.61Ωb)3.84Ωc)4.85Ωd)1.71ΩCorrect answer is option 'D'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about A 50 kVA, 500 V, single phase a.c. generator gave the following test results:Open circuit test: A field current of 12 A produced an e.m.f. of 300 V.Short circuit test: A field current of 12 A caused a current of 175 A to flow in the short-circuited armature.The synchronous impedance of the generator isa)2.61Ωb)3.84Ωc)4.85Ωd)1.71ΩCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 50 kVA, 500 V, single phase a.c. generator gave the following test results:Open circuit test: A field current of 12 A produced an e.m.f. of 300 V.Short circuit test: A field current of 12 A caused a current of 175 A to flow in the short-circuited armature.The synchronous impedance of the generator isa)2.61Ωb)3.84Ωc)4.85Ωd)1.71ΩCorrect answer is option 'D'. Can you explain this answer?.
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ample number of questions to practice A 50 kVA, 500 V, single phase a.c. generator gave the following test results:Open circuit test: A field current of 12 A produced an e.m.f. of 300 V.Short circuit test: A field current of 12 A caused a current of 175 A to flow in the short-circuited armature.The synchronous impedance of the generator isa)2.61Ωb)3.84Ωc)4.85Ωd)1.71ΩCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice SSC tests.
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