A cylinder of 0.12 m radius rotates concentrically inside a fixed hol...
Given:
- Radius of inner cylinder, r1 = 0.12 m
- Radius of outer cylinder, r2 = 0.13 m
- Length of both cylinders, h = 0.3 m
- Torque required to maintain angular velocity, τ = 0.88 Nm
- Angular velocity, ω = 2π rad/s
To find: Viscosity of the liquid filling the space between the cylinders
Assumptions:
- The flow is laminar
- The fluid is incompressible and homogeneous
- The cylinders are infinite in length and there is no end effect
Formula used:
- Torque, τ = 2πηL[(r2^3 - r1^3)/3r2r1]ω
- where, η is the viscosity of the fluid, L is the length of the cylinders, and ω is the angular velocity
Calculation:
- Substituting the given values in the above formula, we get
- 0.88 = 2πη(0.3)[(0.13^3 - 0.12^3)/(3*0.13*0.12)](2π)
- Solving for η, we get
- η = 0.397 Pa.s
Therefore, the viscosity of the liquid filling the space between the cylinders is 0.397 Pa.s
Answer: Option D
A cylinder of 0.12 m radius rotates concentrically inside a fixed hol...
Torque = Shear stress × Surface area × Torque arm