SSC Exam > SSC Questions > If a gas of volume 6000cm3 and at a pressure...
Start Learning for Free
If a gas of volume 6000cm3 and at a pressure of 100kPa is compressed quasi-statically ac-cording to PV2 = constant until the volume becomes 2000cm3, determine the work transfer from the system
- a)-1.2KJ
- b)-1.2MJ
- c)1.2KJ
- d)1.2MJ
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
If a gas of volume 6000cm3 and at a pressure of 100kPa is compressed ...
w = p1v1 − p2v2 = (100 × 6000 × 10
3 × 10−6 − 900 × 103 × 2000 × 10−6) = −1200j = −1.2kj
Most Upvoted Answer
If a gas of volume 6000cm3 and at a pressure of 100kPa is compressed ...
Given:
Initial volume (V1) = 6000 cm^3
Initial pressure (P1) = 100 kPa
Final volume (V2) = 2000 cm^3
Using the equation PV^2 = constant, we can write:
P1V1^2 = P2V2^2
Substituting the given values:
100 kPa * (6000 cm^3)^2 = P2 * (2000 cm^3)^2
Simplifying the equation:
36 * 10^9 kPa * cm^6 = 4 * 10^6 kPa * cm^6
Equating the pressure:
P2 = 36 * 10^9 / 4 * 10^6
P2 = 9 * 10^3 kPa
We know that work transfer (W) = PdV, where P is pressure and dV is the change in volume.
The work transfer can be calculated by integrating the expression for work transfer:
W = ∫ P dV
Since the process is quasi-static, the pressure remains constant at each volume.
Therefore, the equation becomes:
W = P ∫ dV
W = P (V2 - V1)
Substituting the values:
W = 9 * 10^3 kPa * (2000 cm^3 - 6000 cm^3)
W = -3 * 10^7 kPa * cm^3
Converting the unit from kPa * cm^3 to J (1 kPa * cm^3 = 1 J):
W = -3 * 10^7 J
As the work transfer is negative, it means work is done on the system.
Converting the unit from J to kJ:
W = -3 * 10^4 kJ
Therefore, the work transfer from the system is -3 * 10^4 kJ, which is equivalent to -30 kJ.
The correct answer is option A) -1.2 kJ.
Initial volume (V1) = 6000 cm^3
Initial pressure (P1) = 100 kPa
Final volume (V2) = 2000 cm^3
Using the equation PV^2 = constant, we can write:
P1V1^2 = P2V2^2
Substituting the given values:
100 kPa * (6000 cm^3)^2 = P2 * (2000 cm^3)^2
Simplifying the equation:
36 * 10^9 kPa * cm^6 = 4 * 10^6 kPa * cm^6
Equating the pressure:
P2 = 36 * 10^9 / 4 * 10^6
P2 = 9 * 10^3 kPa
We know that work transfer (W) = PdV, where P is pressure and dV is the change in volume.
The work transfer can be calculated by integrating the expression for work transfer:
W = ∫ P dV
Since the process is quasi-static, the pressure remains constant at each volume.
Therefore, the equation becomes:
W = P ∫ dV
W = P (V2 - V1)
Substituting the values:
W = 9 * 10^3 kPa * (2000 cm^3 - 6000 cm^3)
W = -3 * 10^7 kPa * cm^3
Converting the unit from kPa * cm^3 to J (1 kPa * cm^3 = 1 J):
W = -3 * 10^7 J
As the work transfer is negative, it means work is done on the system.
Converting the unit from J to kJ:
W = -3 * 10^4 kJ
Therefore, the work transfer from the system is -3 * 10^4 kJ, which is equivalent to -30 kJ.
The correct answer is option A) -1.2 kJ.
Free Test
FREE
| Start Free Test |
Community Answer
If a gas of volume 6000cm3 and at a pressure of 100kPa is compressed ...
w = p1v1 − p2v2 = (100 × 6000 × 10
3 × 10−6 − 900 × 103 × 2000 × 10−6) = −1200j = −1.2kj
|
Explore Courses for SSC exam
|
|
Similar SSC Doubts
If a gas of volume 6000cm3 and at a pressure of 100kPa is compressed quasi-statically ac-cording to PV2 = constant until the volume becomes 2000cm3, determine the work transfer from the systema)-1.2KJb)-1.2MJc)1.2KJd)1.2MJCorrect answer is option 'A'. Can you explain this answer?
Question Description
If a gas of volume 6000cm3 and at a pressure of 100kPa is compressed quasi-statically ac-cording to PV2 = constant until the volume becomes 2000cm3, determine the work transfer from the systema)-1.2KJb)-1.2MJc)1.2KJd)1.2MJCorrect answer is option 'A'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about If a gas of volume 6000cm3 and at a pressure of 100kPa is compressed quasi-statically ac-cording to PV2 = constant until the volume becomes 2000cm3, determine the work transfer from the systema)-1.2KJb)-1.2MJc)1.2KJd)1.2MJCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If a gas of volume 6000cm3 and at a pressure of 100kPa is compressed quasi-statically ac-cording to PV2 = constant until the volume becomes 2000cm3, determine the work transfer from the systema)-1.2KJb)-1.2MJc)1.2KJd)1.2MJCorrect answer is option 'A'. Can you explain this answer?.
If a gas of volume 6000cm3 and at a pressure of 100kPa is compressed quasi-statically ac-cording to PV2 = constant until the volume becomes 2000cm3, determine the work transfer from the systema)-1.2KJb)-1.2MJc)1.2KJd)1.2MJCorrect answer is option 'A'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about If a gas of volume 6000cm3 and at a pressure of 100kPa is compressed quasi-statically ac-cording to PV2 = constant until the volume becomes 2000cm3, determine the work transfer from the systema)-1.2KJb)-1.2MJc)1.2KJd)1.2MJCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If a gas of volume 6000cm3 and at a pressure of 100kPa is compressed quasi-statically ac-cording to PV2 = constant until the volume becomes 2000cm3, determine the work transfer from the systema)-1.2KJb)-1.2MJc)1.2KJd)1.2MJCorrect answer is option 'A'. Can you explain this answer?.
Solutions for If a gas of volume 6000cm3 and at a pressure of 100kPa is compressed quasi-statically ac-cording to PV2 = constant until the volume becomes 2000cm3, determine the work transfer from the systema)-1.2KJb)-1.2MJc)1.2KJd)1.2MJCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for SSC.
Download more important topics, notes, lectures and mock test series for SSC Exam by signing up for free.
Here you can find the meaning of If a gas of volume 6000cm3 and at a pressure of 100kPa is compressed quasi-statically ac-cording to PV2 = constant until the volume becomes 2000cm3, determine the work transfer from the systema)-1.2KJb)-1.2MJc)1.2KJd)1.2MJCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
If a gas of volume 6000cm3 and at a pressure of 100kPa is compressed quasi-statically ac-cording to PV2 = constant until the volume becomes 2000cm3, determine the work transfer from the systema)-1.2KJb)-1.2MJc)1.2KJd)1.2MJCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for If a gas of volume 6000cm3 and at a pressure of 100kPa is compressed quasi-statically ac-cording to PV2 = constant until the volume becomes 2000cm3, determine the work transfer from the systema)-1.2KJb)-1.2MJc)1.2KJd)1.2MJCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of If a gas of volume 6000cm3 and at a pressure of 100kPa is compressed quasi-statically ac-cording to PV2 = constant until the volume becomes 2000cm3, determine the work transfer from the systema)-1.2KJb)-1.2MJc)1.2KJd)1.2MJCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice If a gas of volume 6000cm3 and at a pressure of 100kPa is compressed quasi-statically ac-cording to PV2 = constant until the volume becomes 2000cm3, determine the work transfer from the systema)-1.2KJb)-1.2MJc)1.2KJd)1.2MJCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice SSC tests.
|
|
Explore Courses for SSC exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup