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The values of the material constants for thermistors P and Q are 4000 K and 3000 K, respectively. The resistance of each thermistor at 298 K is 2 kΩ . At 373 K, the ratio of the resistance of thermistor P to that of thermistor Q will be closest to
- a)1.33
- b)1.00
- c)0.75
- d)0.50
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
The values of the material constants for thermistors P and Q are 4000 ...
RT1 = RT2 exp
For thermistor P,
RT1 = 0.1345
For thermistor Q,
RT1 = 0.264
Then, ratio of resistance of thermistor P to thermistor Q = 0.264/0.1345 = 0.50
Most Upvoted Answer
The values of the material constants for thermistors P and Q are 4000 ...
The resistance-temperature relationship for thermistors can be expressed using the Steinhart-Hart equation:
1/T = a + b * ln(R) + c * (ln(R))^3
where T is the temperature in Kelvin, R is the resistance in ohms, and a, b, and c are the material constants.
To find the resistance of thermistor P at 298 K, we can rearrange the equation as follows:
1/298 = a + b * ln(2000) + c * (ln(2000))^3
Similarly, for thermistor Q:
1/298 = a + b * ln(2000) + c * (ln(2000))^3
Given that the values of the material constants for thermistors P and Q are 4000 K and 3000 K respectively, we can substitute these values into the equations above and solve for a, b, and c.
1/T = a + b * ln(R) + c * (ln(R))^3
where T is the temperature in Kelvin, R is the resistance in ohms, and a, b, and c are the material constants.
To find the resistance of thermistor P at 298 K, we can rearrange the equation as follows:
1/298 = a + b * ln(2000) + c * (ln(2000))^3
Similarly, for thermistor Q:
1/298 = a + b * ln(2000) + c * (ln(2000))^3
Given that the values of the material constants for thermistors P and Q are 4000 K and 3000 K respectively, we can substitute these values into the equations above and solve for a, b, and c.
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The values of the material constants for thermistors P and Q are 4000 K and 3000 K, respectively. The resistance of each thermistor at 298 K is 2 kΩ . At 373 K, the ratio of the resistance of thermistor P to that of thermistor Q will be closest toa)1.33b)1.00c)0.75d)0.50Correct answer is option 'D'. Can you explain this answer?
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The values of the material constants for thermistors P and Q are 4000 K and 3000 K, respectively. The resistance of each thermistor at 298 K is 2 kΩ . At 373 K, the ratio of the resistance of thermistor P to that of thermistor Q will be closest toa)1.33b)1.00c)0.75d)0.50Correct answer is option 'D'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about The values of the material constants for thermistors P and Q are 4000 K and 3000 K, respectively. The resistance of each thermistor at 298 K is 2 kΩ . At 373 K, the ratio of the resistance of thermistor P to that of thermistor Q will be closest toa)1.33b)1.00c)0.75d)0.50Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The values of the material constants for thermistors P and Q are 4000 K and 3000 K, respectively. The resistance of each thermistor at 298 K is 2 kΩ . At 373 K, the ratio of the resistance of thermistor P to that of thermistor Q will be closest toa)1.33b)1.00c)0.75d)0.50Correct answer is option 'D'. Can you explain this answer?.
The values of the material constants for thermistors P and Q are 4000 K and 3000 K, respectively. The resistance of each thermistor at 298 K is 2 kΩ . At 373 K, the ratio of the resistance of thermistor P to that of thermistor Q will be closest toa)1.33b)1.00c)0.75d)0.50Correct answer is option 'D'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about The values of the material constants for thermistors P and Q are 4000 K and 3000 K, respectively. The resistance of each thermistor at 298 K is 2 kΩ . At 373 K, the ratio of the resistance of thermistor P to that of thermistor Q will be closest toa)1.33b)1.00c)0.75d)0.50Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The values of the material constants for thermistors P and Q are 4000 K and 3000 K, respectively. The resistance of each thermistor at 298 K is 2 kΩ . At 373 K, the ratio of the resistance of thermistor P to that of thermistor Q will be closest toa)1.33b)1.00c)0.75d)0.50Correct answer is option 'D'. Can you explain this answer?.
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