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The values of the material constants for thermistors P and Q are 4000 K and 3000 K, respectively. The resistance of each thermistor at 298 K is 2 kΩ . At 373 K, the ratio of the resistance of thermistor P to that of thermistor Q will be closest to
  • a)
    1.33
  • b)
    1.00
  • c)
    0.75
  • d)
    0.50
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The values of the material constants for thermistors P and Q are 4000 ...
RT1 = RT2 exp
For thermistor P,
RT1 = 0.1345
For thermistor Q,
RT1 = 0.264
Then, ratio of resistance of thermistor P to thermistor Q = 0.264/0.1345 = 0.50
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Most Upvoted Answer
The values of the material constants for thermistors P and Q are 4000 ...
The resistance-temperature relationship for thermistors can be expressed using the Steinhart-Hart equation:

1/T = a + b * ln(R) + c * (ln(R))^3

where T is the temperature in Kelvin, R is the resistance in ohms, and a, b, and c are the material constants.

To find the resistance of thermistor P at 298 K, we can rearrange the equation as follows:

1/298 = a + b * ln(2000) + c * (ln(2000))^3

Similarly, for thermistor Q:

1/298 = a + b * ln(2000) + c * (ln(2000))^3

Given that the values of the material constants for thermistors P and Q are 4000 K and 3000 K respectively, we can substitute these values into the equations above and solve for a, b, and c.
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The values of the material constants for thermistors P and Q are 4000 K and 3000 K, respectively. The resistance of each thermistor at 298 K is 2 kΩ . At 373 K, the ratio of the resistance of thermistor P to that of thermistor Q will be closest toa)1.33b)1.00c)0.75d)0.50Correct answer is option 'D'. Can you explain this answer?
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