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A 3-phase Υ-Δ transformer has 420 and 36 turns on the primary and secondary windings respectively. The supply voltage on the primary side is 3.3kV, then what will be the phase voltage on the secondary side of transformer
- a)22260 V
- b)1908 V
- c)164 V
- d)490 V
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A 3-phase Υ-Δ transformer has 420 and 36 turns on the pr...
Winding connection is Y/∆
In 3 transformer
But a may not be equal to N1/N2. So, don’t remember
always in 3- transformer.
In 3 transformer
But a may not be equal to N1/N2. So, don’t remember
always in 3- transformer.Most Upvoted Answer
A 3-phase Υ-Δ transformer has 420 and 36 turns on the pr...
Given Data:
- Primary turns (N1) = 420
- Secondary turns (N2) = 36
- Primary voltage (V1) = 3.3 kV = 3300 V
Formula:
- The ratio of turns is equal to the ratio of voltages in a transformer.
- V2/V1 = N2/N1
Calculations:
- V2 = (N2/N1) * V1
- V2 = (36/420) * 3300
- V2 = 28.57 V
Phase Voltage on Secondary Side:
- Since the given value is the line voltage, for a Υ-Δ transformer, the phase voltage is given by:
- V(phase) = V(line) / √3
- V(phase) = 28.57 / √3
- V(phase) ≈ 16.4 V
Therefore, the phase voltage on the secondary side of the transformer is approximately 16.4 V. Hence, the correct answer is option 'C'.
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