Understanding the Problem
To find the mass of nitrogen that contains the same number of electrons as 4 grams of oxygen, we first need to determine the number of electrons in the oxygen and then relate it to nitrogen.
Electrons in Oxygen
- Oxygen (O) has an atomic number of 8.
- Therefore, each oxygen atom has 8 electrons.
- In 4 grams of oxygen, we need to calculate the number of moles.
Calculating Moles of Oxygen
- The molar mass of oxygen (O2) is approximately 32 g/mol.
- Moles of oxygen in 4 grams = 4 g / 32 g/mol = 0.125 moles.
- Total number of oxygen atoms = 0.125 moles x Avogadro's number (6.022 x 10^23) = 7.5 x 10^22 atoms.
- Total electrons in 4 grams of oxygen = 7.5 x 10^22 atoms x 8 electrons/atom = 6.0 x 10^23 electrons.
Electrons in Nitrogen
- Nitrogen (N) has an atomic number of 7, thus it has 7 electrons per atom.
- To find the moles of nitrogen that contain 6.0 x 10^23 electrons, we calculate the number of nitrogen atoms required.
Calculating Moles of Nitrogen
- Total nitrogen atoms needed = 6.0 x 10^23 electrons / 7 electrons/atom = 8.57 x 10^22 atoms.
- Moles of nitrogen = 8.57 x 10^22 atoms / 6.022 x 10^23 = 0.142 moles.
Finding Mass of Nitrogen
- The molar mass of nitrogen (N2) is approximately 28 g/mol.
- Mass of nitrogen = 0.142 moles x 28 g/mol = 3.976 grams.
Conclusion
Thus, the mass of nitrogen that contains the same number of electrons as 4 grams of oxygen is approximately 4 grams.

Is it 2gm N2?