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The multiplying power of the shunt of a millimeter is 8. If the circuit current is 200 mA, then current through the meter is-
- a)25 mA
- b)200 mA
- c)1600 mA
- d)3200 mA
Correct answer is option 'A'. Can you explain this answer?
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The multiplying power of the shunt of a millimeter is 8. If the circu...
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The multiplying power of the shunt of a millimeter is 8. If the circu...
Given Information:
- Multiplying power of the shunt = 8
- Circuit current = 200 mA
To Find:
Current through the meter
Solution:
The multiplying power of the shunt is the ratio of the full-scale current of the meter to the current passing through the shunt. In this case, the multiplying power is 8, which means that for every 1 unit of current passing through the shunt, the meter will show 8 units of current.
Let's assume the current passing through the shunt is I. Since the multiplying power is 8, the current shown by the meter will be 8I.
We are given the circuit current as 200 mA, which is equivalent to 0.2 A. So, the current passing through the shunt can be calculated as follows:
I = Circuit current - Meter current
I = 0.2 A - 8I
Simplifying the equation, we get:
9I = 0.2 A
I = 0.2 A / 9
I ≈ 0.022 A
Therefore, the current passing through the shunt is approximately 0.022 A.
Now, let's calculate the current shown by the meter:
Meter current = 8I
Meter current = 8 * 0.022 A
Meter current ≈ 0.176 A
Converting the meter current to milliamperes, we get:
Meter current = 0.176 A * 1000 mA/A
Meter current ≈ 176 mA
Therefore, the current shown by the meter is approximately 176 mA, which is equivalent to option A (25 mA) in the given answer choices.
- Multiplying power of the shunt = 8
- Circuit current = 200 mA
To Find:
Current through the meter
Solution:
The multiplying power of the shunt is the ratio of the full-scale current of the meter to the current passing through the shunt. In this case, the multiplying power is 8, which means that for every 1 unit of current passing through the shunt, the meter will show 8 units of current.
Let's assume the current passing through the shunt is I. Since the multiplying power is 8, the current shown by the meter will be 8I.
We are given the circuit current as 200 mA, which is equivalent to 0.2 A. So, the current passing through the shunt can be calculated as follows:
I = Circuit current - Meter current
I = 0.2 A - 8I
Simplifying the equation, we get:
9I = 0.2 A
I = 0.2 A / 9
I ≈ 0.022 A
Therefore, the current passing through the shunt is approximately 0.022 A.
Now, let's calculate the current shown by the meter:
Meter current = 8I
Meter current = 8 * 0.022 A
Meter current ≈ 0.176 A
Converting the meter current to milliamperes, we get:
Meter current = 0.176 A * 1000 mA/A
Meter current ≈ 176 mA
Therefore, the current shown by the meter is approximately 176 mA, which is equivalent to option A (25 mA) in the given answer choices.
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The multiplying power of the shunt of a millimeter is 8. If the circuit current is 200 mA, then current through the meter is-a)25 mAb)200 mAc)1600 mAd)3200 mACorrect answer is option 'A'. Can you explain this answer?
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