A beam simply supported at both the ends of length ‘L’ carries two eq...
Given:
- Beam simply supported at both ends of length 'L'
- Carries two equal unlike couple 'M' at two ends
- Flexure rigidity EI is constant
To find: Central deflection of the beam
Solution:
- Let's consider the beam as shown below:
- We can see that the beam is subjected to a couple moment 'M' at each end.
- Due to this, the beam will undergo bending and the shape of the beam will be as shown below:
- The equation for deflection of a simply supported beam subjected to a point load at the center is given by:
δ = (PL^3)/(48EI)
- Here, the beam is subjected to two point loads at the ends. Hence, we can use the principle of superposition to find the deflection at the center.
- The deflection at the center due to one point load is given by:
δ1 = (ML^2)/(16EI)
- Using the principle of superposition, the deflection at the center due to two point loads is given by:
δ = 2δ1
= 2*(ML^2)/(16EI)
= (ML^2)/(8EI)
- Hence, the central deflection of the beam is given by option 'D': ML^2/8EI.