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A beam simply supported at both the ends of length ‘L’ carries two equal unlike couple ‘M’ at two ends if the flexure rigidity EI is constant. Then the central deflection of the beam is given by-
  • a)
    ML2/4EI
  • b)
    ML2/16EI
  • c)
    ML2/64EI
  • d)
    ML2/8EI
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A beam simply supported at both the ends of length ‘L’ carries two eq...
A beam simply supported at both ends carried two equal, unlike couples at both ends.
The slope at both ends will be equal
AB)
(ML/2EI)
Deflection will be maximum at the center
(△max=△center)(=ML2/8EI)
Hence the option D is correct.
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Most Upvoted Answer
A beam simply supported at both the ends of length ‘L’ carries two eq...
Given:
- Beam simply supported at both ends of length 'L'
- Carries two equal unlike couple 'M' at two ends
- Flexure rigidity EI is constant

To find: Central deflection of the beam

Solution:
- Let's consider the beam as shown below:



- We can see that the beam is subjected to a couple moment 'M' at each end.
- Due to this, the beam will undergo bending and the shape of the beam will be as shown below:



- The equation for deflection of a simply supported beam subjected to a point load at the center is given by:

δ = (PL^3)/(48EI)

- Here, the beam is subjected to two point loads at the ends. Hence, we can use the principle of superposition to find the deflection at the center.
- The deflection at the center due to one point load is given by:

δ1 = (ML^2)/(16EI)

- Using the principle of superposition, the deflection at the center due to two point loads is given by:

δ = 2δ1
= 2*(ML^2)/(16EI)
= (ML^2)/(8EI)

- Hence, the central deflection of the beam is given by option 'D': ML^2/8EI.
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A beam simply supported at both the ends of length ‘L’ carries two equal unlike couple ‘M’ at two ends if the flexure rigidity EI is constant. Then the central deflection of the beam is given by-a)ML2/4EIb)ML2/16EIc)ML2/64EId)ML2/8EICorrect answer is option 'D'. Can you explain this answer?
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