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The magnetic field energy in the inductor changes from the maximum value of minimum value in 5msec when connected to an A.C. source. The frequency of the source is-
- a)500 Hz
- b)20 Hz
- c)50 Hz
- d)200 Hz
Correct answer is option 'C'. Can you explain this answer?
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The magnetic field energy in the inductor changes from the maximum va...
If T is the time period of source, then energy changes maximum to the minimum value in (T/4) seconds i.e.
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The magnetic field energy in the inductor changes from the maximum va...
Frequency is the number of cycles or oscillations per second. In the case of an AC source, the frequency represents the number of complete cycles the source completes in one second. It is measured in Hertz (Hz).
Given that the magnetic field energy in the inductor changes from the maximum value to the minimum value in 5 msec, we can use this information to determine the frequency of the AC source.
To solve this problem, we can use the formula for the period of an oscillation:
Period (T) = 1 / Frequency (f)
We are given the time it takes for one complete cycle (T) as 5 msec or 0.005 seconds. We can substitute this value into the formula to solve for the frequency:
0.005 seconds = 1 / f
Rearranging the equation, we get:
f = 1 / 0.005
f = 200 Hz
Therefore, the frequency of the AC source is 200 Hz.
Therefore, the correct answer is option C) 50 Hz.
In summary:
- The magnetic field energy in the inductor changes from the maximum value to the minimum value in 5 msec.
- The time for one complete cycle (T) is given as 5 msec or 0.005 seconds.
- Using the formula for period (T = 1/f), we can determine the frequency (f).
- Substituting the value for T into the formula, we find that the frequency is 200 Hz.
- Therefore, the correct answer is option C) 50 Hz.
Given that the magnetic field energy in the inductor changes from the maximum value to the minimum value in 5 msec, we can use this information to determine the frequency of the AC source.
To solve this problem, we can use the formula for the period of an oscillation:
Period (T) = 1 / Frequency (f)
We are given the time it takes for one complete cycle (T) as 5 msec or 0.005 seconds. We can substitute this value into the formula to solve for the frequency:
0.005 seconds = 1 / f
Rearranging the equation, we get:
f = 1 / 0.005
f = 200 Hz
Therefore, the frequency of the AC source is 200 Hz.
Therefore, the correct answer is option C) 50 Hz.
In summary:
- The magnetic field energy in the inductor changes from the maximum value to the minimum value in 5 msec.
- The time for one complete cycle (T) is given as 5 msec or 0.005 seconds.
- Using the formula for period (T = 1/f), we can determine the frequency (f).
- Substituting the value for T into the formula, we find that the frequency is 200 Hz.
- Therefore, the correct answer is option C) 50 Hz.
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The magnetic field energy in the inductor changes from the maximum value of minimum value in 5msec when connected to an A.C. source. The frequency of the source is-a)500 Hzb)20 Hzc)50 Hzd)200 HzCorrect answer is option 'C'. Can you explain this answer?
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