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Given: The potential energy of two electrons separated by Bohr radius is 27.211 eV. The first Bohr
radius of hydrogen is 0.5292 Å. The electron makes an orbit of radius 0.5295Å around the nucleus
in hydrogen. The calculated ionization energy (eV) of hydrogen atom is __________.
radius of hydrogen is 0.5292 Å. The electron makes an orbit of radius 0.5295Å around the nucleus
in hydrogen. The calculated ionization energy (eV) of hydrogen atom is __________.
Correct answer is between '13.55,13.64'. Can you explain this answer?
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Given: The potential energy of two electrons separated by Bohr radius ...
Solution:
The potential energy of two electrons separated by Bohr radius is given by the formula:
E = (ke^2) / r
where ke is Coulomb's constant, e is the charge of an electron, and r is the distance between the two electrons.
The first Bohr radius of hydrogen is given as 0.5292 Å, which is equal to 0.5292 x 10^-10 meters.
We can convert this to electron volts (eV) using the formula:
1 eV = 1.602 x 10^-19 J
1 Å = 1 x 10^-10 meters
Therefore, 1 eV/Å = (1.602 x 10^-19 J) / (1 x 10^-10 meters) = 1.602 x 10^-9 J/m
We can substitute the values in the formula for potential energy:
27.211 eV = (ke^2) / (0.5292 x 10^-10 meters)
Solving for ke, we get:
ke^2 = 27.211 eV x 0.5292 x 10^-10 meters
ke^2 = 1.443 x 10^-18 J
ke = sqrt(1.443 x 10^-18) = 3.81 x 10^-9 J.m/e^2
Therefore, the value of ke is 3.81 x 10^-9 J.m/e^2.
The potential energy of two electrons separated by Bohr radius is given by the formula:
E = (ke^2) / r
where ke is Coulomb's constant, e is the charge of an electron, and r is the distance between the two electrons.
The first Bohr radius of hydrogen is given as 0.5292 Å, which is equal to 0.5292 x 10^-10 meters.
We can convert this to electron volts (eV) using the formula:
1 eV = 1.602 x 10^-19 J
1 Å = 1 x 10^-10 meters
Therefore, 1 eV/Å = (1.602 x 10^-19 J) / (1 x 10^-10 meters) = 1.602 x 10^-9 J/m
We can substitute the values in the formula for potential energy:
27.211 eV = (ke^2) / (0.5292 x 10^-10 meters)
Solving for ke, we get:
ke^2 = 27.211 eV x 0.5292 x 10^-10 meters
ke^2 = 1.443 x 10^-18 J
ke = sqrt(1.443 x 10^-18) = 3.81 x 10^-9 J.m/e^2
Therefore, the value of ke is 3.81 x 10^-9 J.m/e^2.
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Given: The potential energy of two electrons separated by Bohr radius is 27.211 eV. The first Bohrradius of hydrogen is 0.5292 Å. The electron makes an orbit of radius 0.5295Å around the nucleusin hydrogen. The calculated ionization energy (eV) of hydrogen atom is __________.Correct answer is between '13.55,13.64'. Can you explain this answer?
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Given: The potential energy of two electrons separated by Bohr radius is 27.211 eV. The first Bohrradius of hydrogen is 0.5292 Å. The electron makes an orbit of radius 0.5295Å around the nucleusin hydrogen. The calculated ionization energy (eV) of hydrogen atom is __________.Correct answer is between '13.55,13.64'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Given: The potential energy of two electrons separated by Bohr radius is 27.211 eV. The first Bohrradius of hydrogen is 0.5292 Å. The electron makes an orbit of radius 0.5295Å around the nucleusin hydrogen. The calculated ionization energy (eV) of hydrogen atom is __________.Correct answer is between '13.55,13.64'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given: The potential energy of two electrons separated by Bohr radius is 27.211 eV. The first Bohrradius of hydrogen is 0.5292 Å. The electron makes an orbit of radius 0.5295Å around the nucleusin hydrogen. The calculated ionization energy (eV) of hydrogen atom is __________.Correct answer is between '13.55,13.64'. Can you explain this answer?.
Given: The potential energy of two electrons separated by Bohr radius is 27.211 eV. The first Bohrradius of hydrogen is 0.5292 Å. The electron makes an orbit of radius 0.5295Å around the nucleusin hydrogen. The calculated ionization energy (eV) of hydrogen atom is __________.Correct answer is between '13.55,13.64'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Given: The potential energy of two electrons separated by Bohr radius is 27.211 eV. The first Bohrradius of hydrogen is 0.5292 Å. The electron makes an orbit of radius 0.5295Å around the nucleusin hydrogen. The calculated ionization energy (eV) of hydrogen atom is __________.Correct answer is between '13.55,13.64'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given: The potential energy of two electrons separated by Bohr radius is 27.211 eV. The first Bohrradius of hydrogen is 0.5292 Å. The electron makes an orbit of radius 0.5295Å around the nucleusin hydrogen. The calculated ionization energy (eV) of hydrogen atom is __________.Correct answer is between '13.55,13.64'. Can you explain this answer?.
Solutions for Given: The potential energy of two electrons separated by Bohr radius is 27.211 eV. The first Bohrradius of hydrogen is 0.5292 Å. The electron makes an orbit of radius 0.5295Å around the nucleusin hydrogen. The calculated ionization energy (eV) of hydrogen atom is __________.Correct answer is between '13.55,13.64'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
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Given: The potential energy of two electrons separated by Bohr radius is 27.211 eV. The first Bohrradius of hydrogen is 0.5292 Å. The electron makes an orbit of radius 0.5295Å around the nucleusin hydrogen. The calculated ionization energy (eV) of hydrogen atom is __________.Correct answer is between '13.55,13.64'. Can you explain this answer?, a detailed solution for Given: The potential energy of two electrons separated by Bohr radius is 27.211 eV. The first Bohrradius of hydrogen is 0.5292 Å. The electron makes an orbit of radius 0.5295Å around the nucleusin hydrogen. The calculated ionization energy (eV) of hydrogen atom is __________.Correct answer is between '13.55,13.64'. Can you explain this answer? has been provided alongside types of Given: The potential energy of two electrons separated by Bohr radius is 27.211 eV. The first Bohrradius of hydrogen is 0.5292 Å. The electron makes an orbit of radius 0.5295Å around the nucleusin hydrogen. The calculated ionization energy (eV) of hydrogen atom is __________.Correct answer is between '13.55,13.64'. Can you explain this answer? theory, EduRev gives you an
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