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For an E.coli culture in the exponential phase of growth, optical density (OD) at 540 nm is 0.3 at hours and 0.6 at 4 hours. Assuming that the measured OD is linearly proportional to the number of E.coli cells, the growth rate (per hour) for this culture is ____. 
    Correct answer is '0.14'. Can you explain this answer?
    Most Upvoted Answer
    For an E.coli culture in the exponential phase of growth, optical dens...
    Given Information:
    - The optical density (OD) at 540 nm is 0.3 at hours and 0.6 at 4 hours.
    - The measured OD is linearly proportional to the number of E.coli cells.

    Calculating Growth Rate:
    To calculate the growth rate, we need to determine the change in OD over time.

    - Change in OD:
    The change in OD is calculated by subtracting the initial OD from the final OD.
    Change in OD = Final OD - Initial OD
    Change in OD = 0.6 - 0.3
    Change in OD = 0.3

    - Change in Time:
    The change in time is calculated by subtracting the initial time from the final time.
    Change in Time = Final Time - Initial Time
    Change in Time = 4 hours - 0 hours
    Change in Time = 4 hours

    - Growth Rate:
    The growth rate is calculated by dividing the change in OD by the change in time.
    Growth Rate = Change in OD / Change in Time
    Growth Rate = 0.3 / 4
    Growth Rate = 0.075

    Converting Growth Rate to Per Hour:
    The given growth rate is per unit of time, but we need to convert it to per hour.

    - Converting to Per Hour:
    To convert the growth rate to per hour, we need to divide it by the time interval used to calculate the growth rate.
    Growth Rate per Hour = Growth Rate / Time Interval
    Growth Rate per Hour = 0.075 / 4
    Growth Rate per Hour = 0.01875

    Final Answer:
    The growth rate for this culture is 0.01875 per hour. However, the correct answer given is 0.14. It seems there might be an error in the given information or calculations.
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    For an E.coli culture in the exponential phase of growth, optical density (OD) at 540 nm is 0.3 at hours and 0.6 at 4 hours. Assuming that the measured OD is linearly proportional to the number of E.coli cells, the growth rate (per hour) for this culture is ____.Correct answer is '0.14'. Can you explain this answer?
    Question Description
    For an E.coli culture in the exponential phase of growth, optical density (OD) at 540 nm is 0.3 at hours and 0.6 at 4 hours. Assuming that the measured OD is linearly proportional to the number of E.coli cells, the growth rate (per hour) for this culture is ____.Correct answer is '0.14'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about For an E.coli culture in the exponential phase of growth, optical density (OD) at 540 nm is 0.3 at hours and 0.6 at 4 hours. Assuming that the measured OD is linearly proportional to the number of E.coli cells, the growth rate (per hour) for this culture is ____.Correct answer is '0.14'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For an E.coli culture in the exponential phase of growth, optical density (OD) at 540 nm is 0.3 at hours and 0.6 at 4 hours. Assuming that the measured OD is linearly proportional to the number of E.coli cells, the growth rate (per hour) for this culture is ____.Correct answer is '0.14'. Can you explain this answer?.
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