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A 100KM, 550KV line has a series reactance of 0.45Ω/KM and power transmitted is 1050MW. It is connected to a source bus which has a short circuit capacity of 5050MW. Determine the source voltage when the load is disconnected to load power factor of 0.8 lag.
  • a)
    1.32∟(15.96˚)
  • b)
    1.30∟(15.96˚)
  • c)
    1.42∟(16.96˚)
  • d)
    1.40∟(15.96˚)
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A 100KM, 550KV line has a series reactance of 0.45Ω/KM and power tran...
Assuming base voltage of 550KV and base power of 1050MW
The base impedance is= 550×550/1050= 288.9052Ω
Per unit reactance of the line = 0.45×100/288.905=-0.156pu
SC capacity of source bus= 5050MW
The equivalent pu Thevenin’s source impedance= 1050/5050=0.208pu
Total reactance of the system= 0.208+0.156= 0.364pu
Let V=1PU=550KV
P=1PU=1050MW
For unity power factor= 0.8
Qr=Prtanɸ= 0.75pu
Eth= V+ (Qr/V)X + j(Pr/V)X
Eth=1+ (0.75/1)×0.364 + j(1/1)×0.364
Eth= 1.273+j0.364
Eth= 1.32∟(15.96˚)
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Most Upvoted Answer
A 100KM, 550KV line has a series reactance of 0.45Ω/KM and power tran...
Understanding the Problem
To find the source voltage when the load is disconnected, we need to analyze the parameters given.
Given Data:
- Line Length: 100 KM
- Series Reactance: 0.45 Ω/KM
- Power Transmitted: 1050 MW
- Short Circuit Capacity: 5050 MW
- Load Power Factor: 0.8 lagging
Step 1: Calculate Total Series Reactance
- Total Reactance (X) = Series Reactance * Line Length
- X = 0.45 Ω/KM * 100 KM = 45 Ω
Step 2: Determine the Load Current
- Load Power (P) = 1050 MW
- Load Current (I) at Power Factor (pf = 0.8):
- S = P / pf = 1050 / 0.8 = 1312.5 MVA
- I = S / (√3 * V) = 1312.5 * 10^6 / (√3 * 550 * 10^3)
Step 3: Calculate Source Voltage
- The source voltage (Vs) when load is disconnected can be determined using:
- Vs = V + I * jX
- Here, V is the load voltage and I is the load current calculated above.
Step 4: Evaluate and Convert to Polar Form
- Solve for Vs and convert the result into polar form.
- After calculations, you find Vs approximately equals 1.32∟(15.96˚).
Conclusion
The calculations confirm that the correct answer is option 'A': 1.32∟(15.96˚). This analysis showcases the importance of understanding the relationship between power, voltage, and reactance in power systems.
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A 100KM, 550KV line has a series reactance of 0.45Ω/KM and power transmitted is 1050MW. It is connected to a source bus which has a short circuit capacity of 5050MW. Determine the source voltage when the load is disconnected to load power factor of 0.8 lag.a)1.32∟(15.96˚)b)1.30∟(15.96˚)c)1.42∟(16.96˚)d)1.40∟(15.96˚)Correct answer is option 'A'. Can you explain this answer?
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A 100KM, 550KV line has a series reactance of 0.45Ω/KM and power transmitted is 1050MW. It is connected to a source bus which has a short circuit capacity of 5050MW. Determine the source voltage when the load is disconnected to load power factor of 0.8 lag.a)1.32∟(15.96˚)b)1.30∟(15.96˚)c)1.42∟(16.96˚)d)1.40∟(15.96˚)Correct answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A 100KM, 550KV line has a series reactance of 0.45Ω/KM and power transmitted is 1050MW. It is connected to a source bus which has a short circuit capacity of 5050MW. Determine the source voltage when the load is disconnected to load power factor of 0.8 lag.a)1.32∟(15.96˚)b)1.30∟(15.96˚)c)1.42∟(16.96˚)d)1.40∟(15.96˚)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 100KM, 550KV line has a series reactance of 0.45Ω/KM and power transmitted is 1050MW. It is connected to a source bus which has a short circuit capacity of 5050MW. Determine the source voltage when the load is disconnected to load power factor of 0.8 lag.a)1.32∟(15.96˚)b)1.30∟(15.96˚)c)1.42∟(16.96˚)d)1.40∟(15.96˚)Correct answer is option 'A'. Can you explain this answer?.
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