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A generator rated 100 k V A 13.8 kV and having reactance x1 = x2 = 0.1 p.u. and x0 = 0.05 p.u. its neutral being grounded through a current reactor of 0.08 pu. The generator is connected to a connected step up transformer with 0.06 p.u. reactance its neutral being solidly grounded. A double line to ground fault occurs at star side of transformer. Calculate fault current in p.u.
- a)6.71 p.u.
- b)0.71 p.u.
- c)9.71 p.u.
- d)11.71 p.u.
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A generator rated 100 k V A 13.8 kV and having reactance x1 = x2 = 0....
+ve sequence n/w is
-ve sequence n/w is
Zero sequence n/w
Fault current
|If|=3|Ifo|
= 3 x 3.57
= 10.71 p.u.
Most Upvoted Answer
A generator rated 100 k V A 13.8 kV and having reactance x1 = x2 = 0....
Calculation of Fault Current in a Generator-Transformer System
Given Data:
Generator rating = 100 kVA
Generator voltage = 13.8 kV
Reactance of generator (x1 = x2) = 0.1 p.u.
Zero sequence reactance of generator (x0) = 0.05 p.u.
Current reactor reactance = 0.08 p.u.
Transformer reactance = 0.06 p.u.
Fault type = Double line to ground fault
Neutral grounding of generator = through a current reactor
Neutral grounding of transformer = solidly grounded
Step 1: Calculation of per unit values
Base kVA = 100 kVA
Base kV = 13.8 kV
Base impedance = (Base kV)^2 / Base kVA = 13.8^2 / 100 = 1.896 ohms
Per unit impedance (p.u.) = Actual impedance / Base impedance
Reactance of generator (x1 = x2) = 0.1 p.u.
Zero sequence reactance of generator (x0) = 0.05 p.u.
Current reactor reactance = 0.08 p.u.
Transformer reactance = 0.06 p.u.
Step 2: Calculation of equivalent circuit
The equivalent circuit for the generator-transformer system during a double line to ground fault is as follows:
Xeq = [(x1 + x0)/3 + 3x2] + (2x0/3) + (2x1/3) + Xtr
Xeq = [(0.1 + 0.05)/3 + 3(0.1)] + (2*0.05/3) + (2*0.1/3) + 0.06
Xeq = 0.4817 p.u.
Step 3: Calculation of fault current
The fault current in the generator-transformer system can be calculated using the following equation:
Ifault = Vg / (3Xeq + X0)
where Vg is the generator voltage
Ifault = 13.8 kV / [3(0.4817) + 0.05]
Ifault = 0.71 p.u.
Therefore, the fault current in the generator-transformer system during a double line to ground fault is 0.71 p.u. Option B is the correct answer.
Given Data:
Generator rating = 100 kVA
Generator voltage = 13.8 kV
Reactance of generator (x1 = x2) = 0.1 p.u.
Zero sequence reactance of generator (x0) = 0.05 p.u.
Current reactor reactance = 0.08 p.u.
Transformer reactance = 0.06 p.u.
Fault type = Double line to ground fault
Neutral grounding of generator = through a current reactor
Neutral grounding of transformer = solidly grounded
Step 1: Calculation of per unit values
Base kVA = 100 kVA
Base kV = 13.8 kV
Base impedance = (Base kV)^2 / Base kVA = 13.8^2 / 100 = 1.896 ohms
Per unit impedance (p.u.) = Actual impedance / Base impedance
Reactance of generator (x1 = x2) = 0.1 p.u.
Zero sequence reactance of generator (x0) = 0.05 p.u.
Current reactor reactance = 0.08 p.u.
Transformer reactance = 0.06 p.u.
Step 2: Calculation of equivalent circuit
The equivalent circuit for the generator-transformer system during a double line to ground fault is as follows:
Xeq = [(x1 + x0)/3 + 3x2] + (2x0/3) + (2x1/3) + Xtr
Xeq = [(0.1 + 0.05)/3 + 3(0.1)] + (2*0.05/3) + (2*0.1/3) + 0.06
Xeq = 0.4817 p.u.
Step 3: Calculation of fault current
The fault current in the generator-transformer system can be calculated using the following equation:
Ifault = Vg / (3Xeq + X0)
where Vg is the generator voltage
Ifault = 13.8 kV / [3(0.4817) + 0.05]
Ifault = 0.71 p.u.
Therefore, the fault current in the generator-transformer system during a double line to ground fault is 0.71 p.u. Option B is the correct answer.
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A generator rated 100 k V A 13.8 kV and having reactance x1 = x2 = 0.1 p.u. and x0 = 0.05 p.u. its neutral being grounded through a current reactor of 0.08 pu. The generator is connected to a connected step up transformer with 0.06 p.u. reactance its neutral being solidly grounded. A double line to ground fault occurs at star side of transformer. Calculate fault current in p.u.a)6.71 p.u.b)0.71 p.u.c)9.71 p.u.d)11.71 p.u.Correct answer is option 'B'. Can you explain this answer?
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A generator rated 100 k V A 13.8 kV and having reactance x1 = x2 = 0.1 p.u. and x0 = 0.05 p.u. its neutral being grounded through a current reactor of 0.08 pu. The generator is connected to a connected step up transformer with 0.06 p.u. reactance its neutral being solidly grounded. A double line to ground fault occurs at star side of transformer. Calculate fault current in p.u.a)6.71 p.u.b)0.71 p.u.c)9.71 p.u.d)11.71 p.u.Correct answer is option 'B'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A generator rated 100 k V A 13.8 kV and having reactance x1 = x2 = 0.1 p.u. and x0 = 0.05 p.u. its neutral being grounded through a current reactor of 0.08 pu. The generator is connected to a connected step up transformer with 0.06 p.u. reactance its neutral being solidly grounded. A double line to ground fault occurs at star side of transformer. Calculate fault current in p.u.a)6.71 p.u.b)0.71 p.u.c)9.71 p.u.d)11.71 p.u.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A generator rated 100 k V A 13.8 kV and having reactance x1 = x2 = 0.1 p.u. and x0 = 0.05 p.u. its neutral being grounded through a current reactor of 0.08 pu. The generator is connected to a connected step up transformer with 0.06 p.u. reactance its neutral being solidly grounded. A double line to ground fault occurs at star side of transformer. Calculate fault current in p.u.a)6.71 p.u.b)0.71 p.u.c)9.71 p.u.d)11.71 p.u.Correct answer is option 'B'. Can you explain this answer?.
A generator rated 100 k V A 13.8 kV and having reactance x1 = x2 = 0.1 p.u. and x0 = 0.05 p.u. its neutral being grounded through a current reactor of 0.08 pu. The generator is connected to a connected step up transformer with 0.06 p.u. reactance its neutral being solidly grounded. A double line to ground fault occurs at star side of transformer. Calculate fault current in p.u.a)6.71 p.u.b)0.71 p.u.c)9.71 p.u.d)11.71 p.u.Correct answer is option 'B'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A generator rated 100 k V A 13.8 kV and having reactance x1 = x2 = 0.1 p.u. and x0 = 0.05 p.u. its neutral being grounded through a current reactor of 0.08 pu. The generator is connected to a connected step up transformer with 0.06 p.u. reactance its neutral being solidly grounded. A double line to ground fault occurs at star side of transformer. Calculate fault current in p.u.a)6.71 p.u.b)0.71 p.u.c)9.71 p.u.d)11.71 p.u.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A generator rated 100 k V A 13.8 kV and having reactance x1 = x2 = 0.1 p.u. and x0 = 0.05 p.u. its neutral being grounded through a current reactor of 0.08 pu. The generator is connected to a connected step up transformer with 0.06 p.u. reactance its neutral being solidly grounded. A double line to ground fault occurs at star side of transformer. Calculate fault current in p.u.a)6.71 p.u.b)0.71 p.u.c)9.71 p.u.d)11.71 p.u.Correct answer is option 'B'. Can you explain this answer?.
Solutions for A generator rated 100 k V A 13.8 kV and having reactance x1 = x2 = 0.1 p.u. and x0 = 0.05 p.u. its neutral being grounded through a current reactor of 0.08 pu. The generator is connected to a connected step up transformer with 0.06 p.u. reactance its neutral being solidly grounded. A double line to ground fault occurs at star side of transformer. Calculate fault current in p.u.a)6.71 p.u.b)0.71 p.u.c)9.71 p.u.d)11.71 p.u.Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
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A generator rated 100 k V A 13.8 kV and having reactance x1 = x2 = 0.1 p.u. and x0 = 0.05 p.u. its neutral being grounded through a current reactor of 0.08 pu. The generator is connected to a connected step up transformer with 0.06 p.u. reactance its neutral being solidly grounded. A double line to ground fault occurs at star side of transformer. Calculate fault current in p.u.a)6.71 p.u.b)0.71 p.u.c)9.71 p.u.d)11.71 p.u.Correct answer is option 'B'. Can you explain this answer?, a detailed solution for A generator rated 100 k V A 13.8 kV and having reactance x1 = x2 = 0.1 p.u. and x0 = 0.05 p.u. its neutral being grounded through a current reactor of 0.08 pu. The generator is connected to a connected step up transformer with 0.06 p.u. reactance its neutral being solidly grounded. A double line to ground fault occurs at star side of transformer. Calculate fault current in p.u.a)6.71 p.u.b)0.71 p.u.c)9.71 p.u.d)11.71 p.u.Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of A generator rated 100 k V A 13.8 kV and having reactance x1 = x2 = 0.1 p.u. and x0 = 0.05 p.u. its neutral being grounded through a current reactor of 0.08 pu. The generator is connected to a connected step up transformer with 0.06 p.u. reactance its neutral being solidly grounded. A double line to ground fault occurs at star side of transformer. Calculate fault current in p.u.a)6.71 p.u.b)0.71 p.u.c)9.71 p.u.d)11.71 p.u.Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A generator rated 100 k V A 13.8 kV and having reactance x1 = x2 = 0.1 p.u. and x0 = 0.05 p.u. its neutral being grounded through a current reactor of 0.08 pu. The generator is connected to a connected step up transformer with 0.06 p.u. reactance its neutral being solidly grounded. A double line to ground fault occurs at star side of transformer. Calculate fault current in p.u.a)6.71 p.u.b)0.71 p.u.c)9.71 p.u.d)11.71 p.u.Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice GATE tests.
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