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If the shear strength of the work material is 350 MPa, the force required to pierce a circular hole of diameter 20 mm in a 2 mm thick mild steel plate with the help of flat-ended die and punch in a press tool is _____ kN.
- a)121.57
- b)125.48
- c)43.98
- d)130.42
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
If the shear strength of the work material is 350 MPa, the force requ...
Theoretical punch force requires can be calculated from the shear strength.
View all questions of this test
F = Shear strength X perimeter of the hole X thickness of hole
π= 350 N/mm2×π×20 mm×2 mm
=43982.29N
=43.982 kN
Most Upvoted Answer
If the shear strength of the work material is 350 MPa, the force requ...
To calculate the force required to pierce a circular hole in a mild steel plate, we need to consider the shear strength of the material and the dimensions of the hole and plate.
Given data:
Shear strength of the work material (σ) = 350 MPa
Diameter of the hole (d) = 20 mm
Thickness of the plate (t) = 2 mm
The force required to pierce the hole can be calculated using the formula:
Force (F) = Shear strength (σ) * Area of shear (A)
1. Calculating the area of the shear:
The area of the shear can be calculated using the formula:
Area of shear (A) = Perimeter of the hole (P) * Thickness of the plate (t)
2. Calculating the perimeter of the hole:
The perimeter of the hole can be calculated using the formula:
Perimeter of the hole (P) = π * Diameter of the hole (d)
3. Calculating the force required:
Using the above formulas, we can calculate the force required to pierce the hole.
Now, let's calculate step by step:
1. Calculating the perimeter of the hole:
Perimeter of the hole (P) = π * Diameter of the hole (d)
= 3.14 * 20 mm
= 62.8 mm
2. Calculating the area of the shear:
Area of shear (A) = Perimeter of the hole (P) * Thickness of the plate (t)
= 62.8 mm * 2 mm
= 125.6 mm^2
3. Converting the area to square meters:
125.6 mm^2 = 125.6 * 10^-6 m^2
= 0.0001256 m^2
4. Calculating the force required:
Force (F) = Shear strength (σ) * Area of shear (A)
= 350 MPa * 0.0001256 m^2
= 0.04398 kN
Hence, the force required to pierce a circular hole of diameter 20 mm in a 2 mm thick mild steel plate is approximately 0.04398 kN.
Therefore, the correct answer is option 'C' (43.98 kN).
Given data:
Shear strength of the work material (σ) = 350 MPa
Diameter of the hole (d) = 20 mm
Thickness of the plate (t) = 2 mm
The force required to pierce the hole can be calculated using the formula:
Force (F) = Shear strength (σ) * Area of shear (A)
1. Calculating the area of the shear:
The area of the shear can be calculated using the formula:
Area of shear (A) = Perimeter of the hole (P) * Thickness of the plate (t)
2. Calculating the perimeter of the hole:
The perimeter of the hole can be calculated using the formula:
Perimeter of the hole (P) = π * Diameter of the hole (d)
3. Calculating the force required:
Using the above formulas, we can calculate the force required to pierce the hole.
Now, let's calculate step by step:
1. Calculating the perimeter of the hole:
Perimeter of the hole (P) = π * Diameter of the hole (d)
= 3.14 * 20 mm
= 62.8 mm
2. Calculating the area of the shear:
Area of shear (A) = Perimeter of the hole (P) * Thickness of the plate (t)
= 62.8 mm * 2 mm
= 125.6 mm^2
3. Converting the area to square meters:
125.6 mm^2 = 125.6 * 10^-6 m^2
= 0.0001256 m^2
4. Calculating the force required:
Force (F) = Shear strength (σ) * Area of shear (A)
= 350 MPa * 0.0001256 m^2
= 0.04398 kN
Hence, the force required to pierce a circular hole of diameter 20 mm in a 2 mm thick mild steel plate is approximately 0.04398 kN.
Therefore, the correct answer is option 'C' (43.98 kN).
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If the shear strength of the work material is 350 MPa, the force required to pierce a circular hole of diameter 20 mm in a 2 mm thick mild steel plate with the help of flat-ended die and punch in a press tool is _____ kN.a)121.57b)125.48c)43.98d)130.42Correct answer is option 'C'. Can you explain this answer?
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If the shear strength of the work material is 350 MPa, the force required to pierce a circular hole of diameter 20 mm in a 2 mm thick mild steel plate with the help of flat-ended die and punch in a press tool is _____ kN.a)121.57b)125.48c)43.98d)130.42Correct answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about If the shear strength of the work material is 350 MPa, the force required to pierce a circular hole of diameter 20 mm in a 2 mm thick mild steel plate with the help of flat-ended die and punch in a press tool is _____ kN.a)121.57b)125.48c)43.98d)130.42Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the shear strength of the work material is 350 MPa, the force required to pierce a circular hole of diameter 20 mm in a 2 mm thick mild steel plate with the help of flat-ended die and punch in a press tool is _____ kN.a)121.57b)125.48c)43.98d)130.42Correct answer is option 'C'. Can you explain this answer?.
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If the shear strength of the work material is 350 MPa, the force required to pierce a circular hole of diameter 20 mm in a 2 mm thick mild steel plate with the help of flat-ended die and punch in a press tool is _____ kN.a)121.57b)125.48c)43.98d)130.42Correct answer is option 'C'. Can you explain this answer?, a detailed solution for If the shear strength of the work material is 350 MPa, the force required to pierce a circular hole of diameter 20 mm in a 2 mm thick mild steel plate with the help of flat-ended die and punch in a press tool is _____ kN.a)121.57b)125.48c)43.98d)130.42Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of If the shear strength of the work material is 350 MPa, the force required to pierce a circular hole of diameter 20 mm in a 2 mm thick mild steel plate with the help of flat-ended die and punch in a press tool is _____ kN.a)121.57b)125.48c)43.98d)130.42Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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