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An intrinsic semiconductor bar of Si is doped with donor type impurity to the extent of 1 atom per 108 silicon atoms, then the resistivity of silicon crystal will be (atomic density of Si crystals =5 × 1022 atoms /cm3 and μn = 1300cm2N − sec)
Correct answer is '9.61'. Can you explain this answer?
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An intrinsic semiconductor bar of Si is doped with donor type impurit...
∵ It is an n -type semiconductor
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An intrinsic semiconductor bar of Si is doped with donor type impurit...
Given data:
- Type of semiconductor: Intrinsic (pure) Si
- Donor impurity doping concentration: 1 atom per 10^8 Si atoms
- Atomic density of Si crystal: 5 x 10^22 atoms/cm^3
- Electron mobility: μn = 1300 cm^2N-sec

To find: Resistivity of the Si crystal

Formula used:
- Resistivity (ρ) = 1/(q * n * μn)
- q = 1.6 x 10^-19 C (charge of an electron)
- n = donor impurity concentration in Si
- μn = electron mobility

Solution:
1. Calculate the donor impurity concentration in cm^-3:
- 1 atom per 10^8 Si atoms = 10^-8 impurity atoms per Si atom
- Donor impurity concentration = 10^-8 x 5 x 10^22 = 5 x 10^14 cm^-3

2. Calculate resistivity using the formula:
- q = 1.6 x 10^-19 C
- n = 5 x 10^14 cm^-3
- μn = 1300 cm^2N-sec
- ρ = 1/(1.6 x 10^-19 x 5 x 10^14 x 1300)
- ρ = 9.61 Ω-cm

Therefore, the resistivity of the Si crystal doped with donor impurity is 9.61 Ω-cm.
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An intrinsic semiconductor bar of Si is doped with donor type impurity to the extent of 1 atom per 108 silicon atoms, then the resistivity of silicon crystal will be (atomic density of Si crystals =5 × 1022 atoms /cm3 and μn = 1300cm2N − sec)Correct answer is '9.61'. Can you explain this answer?
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