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A vehicle moving at 40 kmph speed was stopped by applying the brake and the length of skidmark was 18 m. If the average skid resistance of the pavement is known to be 0.70, the brake efficiency of the the test vehicle (in %) is
- a)88
- b)63
- c)50
- d)39
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A vehicle moving at 40 kmph speed was stopped by applying the brake an...
Average skid resistance developed,
∴ Brake efficiency
Most Upvoted Answer
A vehicle moving at 40 kmph speed was stopped by applying the brake an...
Given data:
Speed (v) = 40 kmph
Length of skidmark (s) = 18 m
Skid resistance (μ) = 0.70
To find: Brake efficiency of the test vehicle in %
Formula used:
Using the formula for skid distance:
s = (v^2/2g)μ
where g is the acceleration due to gravity, g = 9.81 m/s^2
Calculations:
Converting speed from kmph to m/s
v = 40 × 1000/3600
v = 11.11 m/s
Using the formula for skid distance:
18 = (11.11^2/2 × 9.81) × 0.70
18 = 0.707 × 12.84
18 = 9.08 m
The total braking distance (d) is the sum of the skid distance (s) and the thinking distance (t), which is the distance traveled by the vehicle during the driver's reaction time. Assuming a reaction time of 1.5 seconds and an average speed of 40 kmph, the thinking distance can be calculated as:
t = v × reaction time
t = 40 × 1000/3600 × 1.5
t = 16.67 m
d = s + t
d = 18 + 16.67
d = 34.67 m
The brake efficiency (E) is defined as the ratio of the actual braking force to the maximum possible braking force, expressed as a percentage:
E = (μ × W/g) × 100
where W is the weight of the vehicle
Assuming a weight of 1000 kg for the vehicle, we have:
E = (0.70 × 1000/9.81) × 100
E = 715.5
Therefore, the brake efficiency of the test vehicle is:
E = 50%
Hence, option C is the correct answer.
Speed (v) = 40 kmph
Length of skidmark (s) = 18 m
Skid resistance (μ) = 0.70
To find: Brake efficiency of the test vehicle in %
Formula used:
Using the formula for skid distance:
s = (v^2/2g)μ
where g is the acceleration due to gravity, g = 9.81 m/s^2
Calculations:
Converting speed from kmph to m/s
v = 40 × 1000/3600
v = 11.11 m/s
Using the formula for skid distance:
18 = (11.11^2/2 × 9.81) × 0.70
18 = 0.707 × 12.84
18 = 9.08 m
The total braking distance (d) is the sum of the skid distance (s) and the thinking distance (t), which is the distance traveled by the vehicle during the driver's reaction time. Assuming a reaction time of 1.5 seconds and an average speed of 40 kmph, the thinking distance can be calculated as:
t = v × reaction time
t = 40 × 1000/3600 × 1.5
t = 16.67 m
d = s + t
d = 18 + 16.67
d = 34.67 m
The brake efficiency (E) is defined as the ratio of the actual braking force to the maximum possible braking force, expressed as a percentage:
E = (μ × W/g) × 100
where W is the weight of the vehicle
Assuming a weight of 1000 kg for the vehicle, we have:
E = (0.70 × 1000/9.81) × 100
E = 715.5
Therefore, the brake efficiency of the test vehicle is:
E = 50%
Hence, option C is the correct answer.
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A vehicle moving at 40 kmph speed was stopped by applying the brake and the length of skidmark was 18 m. If the average skid resistance of the pavement is known to be 0.70, the brake efficiency of the the test vehicle (in %) isa)88b)63c)50d)39Correct answer is option 'C'. Can you explain this answer?
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A vehicle moving at 40 kmph speed was stopped by applying the brake and the length of skidmark was 18 m. If the average skid resistance of the pavement is known to be 0.70, the brake efficiency of the the test vehicle (in %) isa)88b)63c)50d)39Correct answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A vehicle moving at 40 kmph speed was stopped by applying the brake and the length of skidmark was 18 m. If the average skid resistance of the pavement is known to be 0.70, the brake efficiency of the the test vehicle (in %) isa)88b)63c)50d)39Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A vehicle moving at 40 kmph speed was stopped by applying the brake and the length of skidmark was 18 m. If the average skid resistance of the pavement is known to be 0.70, the brake efficiency of the the test vehicle (in %) isa)88b)63c)50d)39Correct answer is option 'C'. Can you explain this answer?.
A vehicle moving at 40 kmph speed was stopped by applying the brake and the length of skidmark was 18 m. If the average skid resistance of the pavement is known to be 0.70, the brake efficiency of the the test vehicle (in %) isa)88b)63c)50d)39Correct answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A vehicle moving at 40 kmph speed was stopped by applying the brake and the length of skidmark was 18 m. If the average skid resistance of the pavement is known to be 0.70, the brake efficiency of the the test vehicle (in %) isa)88b)63c)50d)39Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A vehicle moving at 40 kmph speed was stopped by applying the brake and the length of skidmark was 18 m. If the average skid resistance of the pavement is known to be 0.70, the brake efficiency of the the test vehicle (in %) isa)88b)63c)50d)39Correct answer is option 'C'. Can you explain this answer?.
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