In a spot welding process, a current of 40,000 amperes is released for 0.015 sec. The effective resistance of the joint is 120 micro ohm. The joint can be considered as a cylinder of 6 mm diameter and 3mm height. The heat required for the melting of material is 10 J/mm3. Calculate the heat transferred to environment (in kcalories) from the joint where 4.184 joules = 1 caloriesCorrect answer is '0.485'. Can you explain this answer?

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In a spot welding process, a current of 40,000 amperes is released for 0.015 sec. The effective resistance of the joint is 120 micro ohm. The joint can be considered as a cylinder of 6 mm diameter and 3mm height. The heat required for the melting of material is 10 J/mm³. Calculate the heat transferred to environment (in kcalories) from the joint where 4.184 joules = 1 calories

Correct answer is '0.485'. Can you explain this answer?

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In a spot welding process, a current of 40,000 amperes is released fo...

Heat Supplied =I2RT

=(40000)² × 120 × 10^-6 × 0.015

=2880 Joules

Heat required = π/4d² × H × e

= π/4 × 6² × 3 × 10

= 848.23

Heat escape to surrounding = 2880 − 848.23

= 2031.76 joules = 485.60 calories = 0.485 kcal

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In a spot welding process, a current of 40,000 amperes is released for 0.015 sec. The effective resistance of the joint is 120 micro ohm. The joint can be considered as a cylinder of 6 mm diameter and 3mm height. The heat required for the melting of material is 10 J/mm3. Calculate the heat transferred to environment (in kcalories) from the joint where 4.184 joules = 1 caloriesCorrect answer is '0.485'. Can you explain this answer?

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In a spot welding process, a current of 40,000 amperes is released for 0.015 sec. The effective resistance of the joint is 120 micro ohm. The joint can be considered as a cylinder of 6 mm diameter and 3mm height. The heat required for the melting of material is 10 J/mm3. Calculate the heat transferred to environment (in kcalories) from the joint where 4.184 joules = 1 caloriesCorrect answer is '0.485'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about In a spot welding process, a current of 40,000 amperes is released for 0.015 sec. The effective resistance of the joint is 120 micro ohm. The joint can be considered as a cylinder of 6 mm diameter and 3mm height. The heat required for the melting of material is 10 J/mm3. Calculate the heat transferred to environment (in kcalories) from the joint where 4.184 joules = 1 caloriesCorrect answer is '0.485'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a spot welding process, a current of 40,000 amperes is released for 0.015 sec. The effective resistance of the joint is 120 micro ohm. The joint can be considered as a cylinder of 6 mm diameter and 3mm height. The heat required for the melting of material is 10 J/mm3. Calculate the heat transferred to environment (in kcalories) from the joint where 4.184 joules = 1 caloriesCorrect answer is '0.485'. Can you explain this answer?.

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