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1 g of Mg is burnt in a closed vessel containing 0.5 g of O2. Which reactant is limiting reagent and how much of the excess reactant will be left?
- a)O2 is a limiting reagent and Mg is in excess by 0.25 g
- b)Mg is a limiting reagent and is in excess by 0.5 g
- c)O2 is a limiting reagent and is in excess by 0.25 g
- d)O2 is a limiting reagent and Mg is in excess by 0.75 g
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
1 g of Mg is burnt in a closed vessel containing 0.5 g of O2. Which re...
48 g of Mg requires 32 g of O2
1 g of Mg requires 32/48 = 0.66 g of O2
Oxygen available = 0.5 g
Hence, O2 is limiting reagent.
32 g of O2 reacts with 48 g of Mg
0.5 g of O2 will react with 48/32 x 0.5 = 0.75 g of Mg
Excess of Mg = (1.0 - 0.75) = 0.25 g
Most Upvoted Answer
1 g of Mg is burnt in a closed vessel containing 0.5 g of O2. Which re...
Given:
Mass of Mg = 1 g
Mass of O2 = 0.5 g
To determine the limiting reagent and the excess reagent:
Step 1: Write the balanced chemical equation for the reaction between Mg and O2.
2Mg + O2 → 2MgO
Step 2: Calculate the moles of each reactant.
Moles of Mg = mass of Mg / molar mass of Mg
= 1 g / 24.31 g/mol
= 0.041 moles
Moles of O2 = mass of O2 / molar mass of O2
= 0.5 g / 32 g/mol
= 0.016 moles
Step 3: Determine the limiting reagent.
The reactant that produces the least amount of product is the limiting reagent.
Using the balanced equation:
2 moles of Mg reacts with 1 mole of O2 to produce 2 moles of MgO.
Therefore, 0.016 moles of O2 would require 0.032 moles of Mg to react completely.
Since the amount of Mg available (0.041 moles) is greater than the amount required (0.032 moles), Mg is in excess while O2 is the limiting reagent.
Step 4: Calculate the excess reagent.
The amount of excess reagent can be calculated by subtracting the amount of limiting reagent used from the initial amount of the reactant.
Amount of Mg used = 0.016 moles (since 1 mole of O2 reacts with 2 moles of Mg)
Amount of Mg in excess = 0.041 moles - 0.016 moles = 0.025 moles
Excess mass of Mg = amount of Mg in excess × molar mass of Mg
= 0.025 moles × 24.31 g/mol
= 0.6075 g
Therefore, the correct answer is option A: O2 is the limiting reagent and Mg is in excess by 0.25 g.
Mass of Mg = 1 g
Mass of O2 = 0.5 g
To determine the limiting reagent and the excess reagent:
Step 1: Write the balanced chemical equation for the reaction between Mg and O2.
2Mg + O2 → 2MgO
Step 2: Calculate the moles of each reactant.
Moles of Mg = mass of Mg / molar mass of Mg
= 1 g / 24.31 g/mol
= 0.041 moles
Moles of O2 = mass of O2 / molar mass of O2
= 0.5 g / 32 g/mol
= 0.016 moles
Step 3: Determine the limiting reagent.
The reactant that produces the least amount of product is the limiting reagent.
Using the balanced equation:
2 moles of Mg reacts with 1 mole of O2 to produce 2 moles of MgO.
Therefore, 0.016 moles of O2 would require 0.032 moles of Mg to react completely.
Since the amount of Mg available (0.041 moles) is greater than the amount required (0.032 moles), Mg is in excess while O2 is the limiting reagent.
Step 4: Calculate the excess reagent.
The amount of excess reagent can be calculated by subtracting the amount of limiting reagent used from the initial amount of the reactant.
Amount of Mg used = 0.016 moles (since 1 mole of O2 reacts with 2 moles of Mg)
Amount of Mg in excess = 0.041 moles - 0.016 moles = 0.025 moles
Excess mass of Mg = amount of Mg in excess × molar mass of Mg
= 0.025 moles × 24.31 g/mol
= 0.6075 g
Therefore, the correct answer is option A: O2 is the limiting reagent and Mg is in excess by 0.25 g.
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1 g of Mg is burnt in a closed vessel containing 0.5 g of O2. Which reactant is limiting reagent and how much of the excess reactant will be left?a)O2 is a limiting reagent and Mg is in excess by 0.25 gb)Mg is a limiting reagent and is in excess by 0.5 gc)O2 is a limiting reagent and is in excess by 0.25 gd)O2 is a limiting reagent and Mg is in excess by 0.75 gCorrect answer is option 'A'. Can you explain this answer?
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1 g of Mg is burnt in a closed vessel containing 0.5 g of O2. Which reactant is limiting reagent and how much of the excess reactant will be left?a)O2 is a limiting reagent and Mg is in excess by 0.25 gb)Mg is a limiting reagent and is in excess by 0.5 gc)O2 is a limiting reagent and is in excess by 0.25 gd)O2 is a limiting reagent and Mg is in excess by 0.75 gCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 1 g of Mg is burnt in a closed vessel containing 0.5 g of O2. Which reactant is limiting reagent and how much of the excess reactant will be left?a)O2 is a limiting reagent and Mg is in excess by 0.25 gb)Mg is a limiting reagent and is in excess by 0.5 gc)O2 is a limiting reagent and is in excess by 0.25 gd)O2 is a limiting reagent and Mg is in excess by 0.75 gCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 1 g of Mg is burnt in a closed vessel containing 0.5 g of O2. Which reactant is limiting reagent and how much of the excess reactant will be left?a)O2 is a limiting reagent and Mg is in excess by 0.25 gb)Mg is a limiting reagent and is in excess by 0.5 gc)O2 is a limiting reagent and is in excess by 0.25 gd)O2 is a limiting reagent and Mg is in excess by 0.75 gCorrect answer is option 'A'. Can you explain this answer?.
1 g of Mg is burnt in a closed vessel containing 0.5 g of O2. Which reactant is limiting reagent and how much of the excess reactant will be left?a)O2 is a limiting reagent and Mg is in excess by 0.25 gb)Mg is a limiting reagent and is in excess by 0.5 gc)O2 is a limiting reagent and is in excess by 0.25 gd)O2 is a limiting reagent and Mg is in excess by 0.75 gCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 1 g of Mg is burnt in a closed vessel containing 0.5 g of O2. Which reactant is limiting reagent and how much of the excess reactant will be left?a)O2 is a limiting reagent and Mg is in excess by 0.25 gb)Mg is a limiting reagent and is in excess by 0.5 gc)O2 is a limiting reagent and is in excess by 0.25 gd)O2 is a limiting reagent and Mg is in excess by 0.75 gCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 1 g of Mg is burnt in a closed vessel containing 0.5 g of O2. Which reactant is limiting reagent and how much of the excess reactant will be left?a)O2 is a limiting reagent and Mg is in excess by 0.25 gb)Mg is a limiting reagent and is in excess by 0.5 gc)O2 is a limiting reagent and is in excess by 0.25 gd)O2 is a limiting reagent and Mg is in excess by 0.75 gCorrect answer is option 'A'. Can you explain this answer?.
Solutions for 1 g of Mg is burnt in a closed vessel containing 0.5 g of O2. Which reactant is limiting reagent and how much of the excess reactant will be left?a)O2 is a limiting reagent and Mg is in excess by 0.25 gb)Mg is a limiting reagent and is in excess by 0.5 gc)O2 is a limiting reagent and is in excess by 0.25 gd)O2 is a limiting reagent and Mg is in excess by 0.75 gCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
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1 g of Mg is burnt in a closed vessel containing 0.5 g of O2. Which reactant is limiting reagent and how much of the excess reactant will be left?a)O2 is a limiting reagent and Mg is in excess by 0.25 gb)Mg is a limiting reagent and is in excess by 0.5 gc)O2 is a limiting reagent and is in excess by 0.25 gd)O2 is a limiting reagent and Mg is in excess by 0.75 gCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for 1 g of Mg is burnt in a closed vessel containing 0.5 g of O2. Which reactant is limiting reagent and how much of the excess reactant will be left?a)O2 is a limiting reagent and Mg is in excess by 0.25 gb)Mg is a limiting reagent and is in excess by 0.5 gc)O2 is a limiting reagent and is in excess by 0.25 gd)O2 is a limiting reagent and Mg is in excess by 0.75 gCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of 1 g of Mg is burnt in a closed vessel containing 0.5 g of O2. Which reactant is limiting reagent and how much of the excess reactant will be left?a)O2 is a limiting reagent and Mg is in excess by 0.25 gb)Mg is a limiting reagent and is in excess by 0.5 gc)O2 is a limiting reagent and is in excess by 0.25 gd)O2 is a limiting reagent and Mg is in excess by 0.75 gCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice 1 g of Mg is burnt in a closed vessel containing 0.5 g of O2. Which reactant is limiting reagent and how much of the excess reactant will be left?a)O2 is a limiting reagent and Mg is in excess by 0.25 gb)Mg is a limiting reagent and is in excess by 0.5 gc)O2 is a limiting reagent and is in excess by 0.25 gd)O2 is a limiting reagent and Mg is in excess by 0.75 gCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice NEET tests.
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