GATE Exam > GATE Questions > A signal of bandwidth 100 MHz and strength 1...
Start Learning for Free
A signal of bandwidth 100 MHz and strength 10mW is transmitted through a transmitter through a cable that has 40 dB loss. If N0/2 = 0.5 × 10−20ω/Hz then the signal to noise ratio at the input of the receiver is
- a)106
- b)105
- c)107
- d)108
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A signal of bandwidth 100 MHz and strength 10mW is transmitted throug...
Most Upvoted Answer
A signal of bandwidth 100 MHz and strength 10mW is transmitted throug...
To calculate the signal-to-noise ratio (SNR) at the input of the receiver, we need to consider the signal strength, the cable loss, and the noise power.
Given information:
Bandwidth (B) = 100 MHz = 100 × 10^6 Hz
Signal Strength (P_s) = 10 mW = 10 × 10^(-3) W
Cable Loss (L) = 40 dB
1. Calculation of Signal Power at the Receiver Input:
The signal power at the receiver input can be calculated using the formula:
P_r = P_s × 10^(-L/10)
Substituting the given values:
P_r = 10 × 10^(-3) × 10^(-40/10)
= 10 × 10^(-3) × 10^(-4)
= 10 × 10^(-7)
= 10^(-6) W
2. Calculation of Noise Power:
The noise power can be calculated using the formula:
N = N0 × B
Given:
N0/2 = 0.5 × 10^(-20) W/Hz
B = 100 × 10^6 Hz
Substituting the values:
N = N0 × B
= (0.5 × 10^(-20)) × (100 × 10^6)
= 0.5 × 10^(-14) W
3. Calculation of SNR at the Receiver Input:
SNR = P_r / N
Substituting the values:
SNR = (10^(-6)) / (0.5 × 10^(-14))
= 10^(-6+14)
= 10^8
Therefore, the signal-to-noise ratio (SNR) at the input of the receiver is 10^8, which is equivalent to option 'A' (106).
Given information:
Bandwidth (B) = 100 MHz = 100 × 10^6 Hz
Signal Strength (P_s) = 10 mW = 10 × 10^(-3) W
Cable Loss (L) = 40 dB
1. Calculation of Signal Power at the Receiver Input:
The signal power at the receiver input can be calculated using the formula:
P_r = P_s × 10^(-L/10)
Substituting the given values:
P_r = 10 × 10^(-3) × 10^(-40/10)
= 10 × 10^(-3) × 10^(-4)
= 10 × 10^(-7)
= 10^(-6) W
2. Calculation of Noise Power:
The noise power can be calculated using the formula:
N = N0 × B
Given:
N0/2 = 0.5 × 10^(-20) W/Hz
B = 100 × 10^6 Hz
Substituting the values:
N = N0 × B
= (0.5 × 10^(-20)) × (100 × 10^6)
= 0.5 × 10^(-14) W
3. Calculation of SNR at the Receiver Input:
SNR = P_r / N
Substituting the values:
SNR = (10^(-6)) / (0.5 × 10^(-14))
= 10^(-6+14)
= 10^8
Therefore, the signal-to-noise ratio (SNR) at the input of the receiver is 10^8, which is equivalent to option 'A' (106).
|
Explore Courses for GATE exam
|
|
A signal of bandwidth 100 MHz and strength 10mW is transmitted through a transmitter through a cable that has 40 dB loss. If N0/2 = 0.5 × 10−20ω/Hz then the signal to noise ratio at the input of the receiver isa)106b)105c)107d)108Correct answer is option 'A'. Can you explain this answer?
Question Description
A signal of bandwidth 100 MHz and strength 10mW is transmitted through a transmitter through a cable that has 40 dB loss. If N0/2 = 0.5 × 10−20ω/Hz then the signal to noise ratio at the input of the receiver isa)106b)105c)107d)108Correct answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A signal of bandwidth 100 MHz and strength 10mW is transmitted through a transmitter through a cable that has 40 dB loss. If N0/2 = 0.5 × 10−20ω/Hz then the signal to noise ratio at the input of the receiver isa)106b)105c)107d)108Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A signal of bandwidth 100 MHz and strength 10mW is transmitted through a transmitter through a cable that has 40 dB loss. If N0/2 = 0.5 × 10−20ω/Hz then the signal to noise ratio at the input of the receiver isa)106b)105c)107d)108Correct answer is option 'A'. Can you explain this answer?.
A signal of bandwidth 100 MHz and strength 10mW is transmitted through a transmitter through a cable that has 40 dB loss. If N0/2 = 0.5 × 10−20ω/Hz then the signal to noise ratio at the input of the receiver isa)106b)105c)107d)108Correct answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A signal of bandwidth 100 MHz and strength 10mW is transmitted through a transmitter through a cable that has 40 dB loss. If N0/2 = 0.5 × 10−20ω/Hz then the signal to noise ratio at the input of the receiver isa)106b)105c)107d)108Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A signal of bandwidth 100 MHz and strength 10mW is transmitted through a transmitter through a cable that has 40 dB loss. If N0/2 = 0.5 × 10−20ω/Hz then the signal to noise ratio at the input of the receiver isa)106b)105c)107d)108Correct answer is option 'A'. Can you explain this answer?.
Solutions for A signal of bandwidth 100 MHz and strength 10mW is transmitted through a transmitter through a cable that has 40 dB loss. If N0/2 = 0.5 × 10−20ω/Hz then the signal to noise ratio at the input of the receiver isa)106b)105c)107d)108Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
Download more important topics, notes, lectures and mock test series for GATE Exam by signing up for free.
Here you can find the meaning of A signal of bandwidth 100 MHz and strength 10mW is transmitted through a transmitter through a cable that has 40 dB loss. If N0/2 = 0.5 × 10−20ω/Hz then the signal to noise ratio at the input of the receiver isa)106b)105c)107d)108Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A signal of bandwidth 100 MHz and strength 10mW is transmitted through a transmitter through a cable that has 40 dB loss. If N0/2 = 0.5 × 10−20ω/Hz then the signal to noise ratio at the input of the receiver isa)106b)105c)107d)108Correct answer is option 'A'. Can you explain this answer?, a detailed solution for A signal of bandwidth 100 MHz and strength 10mW is transmitted through a transmitter through a cable that has 40 dB loss. If N0/2 = 0.5 × 10−20ω/Hz then the signal to noise ratio at the input of the receiver isa)106b)105c)107d)108Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of A signal of bandwidth 100 MHz and strength 10mW is transmitted through a transmitter through a cable that has 40 dB loss. If N0/2 = 0.5 × 10−20ω/Hz then the signal to noise ratio at the input of the receiver isa)106b)105c)107d)108Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A signal of bandwidth 100 MHz and strength 10mW is transmitted through a transmitter through a cable that has 40 dB loss. If N0/2 = 0.5 × 10−20ω/Hz then the signal to noise ratio at the input of the receiver isa)106b)105c)107d)108Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice GATE tests.
|
|
Explore Courses for GATE exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup