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A speech signal, band limited to 5 KHz with peak to peak between +10 V to – 10 V and the signal is sampled at Nyquist rate and the bits 0 and 1 are transmitted using bipolar pulses. What is minimum bandwidth for distortion free transmission ….
  • a)
    40
  • b)
    50
  • c)
    60
  • d)
    55
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A speech signal, band limited to 5 KHz with peak to peak between +10 V...
While using polar pulses, the minimum bandwidth required is four times the theoretical bandwidth or nyquist bandwidth.
Required BW = 4 * Nyquist BW
= 4 × 2 fm = 4 × 2 × 5 KHz = 40 KHz
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Most Upvoted Answer
A speech signal, band limited to 5 KHz with peak to peak between +10 V...
-10 V, is sampled at a rate of 20 KHz. The quantization level is 8 bits.

Ladies and gentlemen,

Today, I would like to talk to you about the fascinating topic of speech signals and their characteristics. Specifically, I will discuss a speech signal that is band-limited to 5 KHz with a peak-to-peak voltage range between 10 V to -10 V. Furthermore, I will delve into the process of sampling this signal and the quantization level used.

Firstly, let's understand what a band-limited signal means. A band-limited signal refers to a signal that has its frequency components limited within a certain range. In this case, our speech signal is restricted to frequencies up to 5 KHz. This is a common frequency range for speech signals as most of the important information for human speech lies within this bandwidth.

Now, let's move on to the sampling of this speech signal. Sampling involves converting a continuous-time signal into a discrete-time representation by taking samples at regular intervals. In our case, the speech signal is sampled at a rate of 20 KHz, which means 20,000 samples are taken every second. This sampling rate is chosen based on the Nyquist-Shannon sampling theorem, which states that the sampling rate must be at least twice the highest frequency component of the signal to avoid aliasing.

Additionally, let's discuss the quantization level used for this speech signal. Quantization is the process of converting the continuous amplitude values of a signal into a finite number of discrete levels. In this case, the signal is quantized using 8 bits, which means there are 2^8 or 256 possible discrete levels. The quantization levels are evenly spaced between the peak-to-peak voltage range of 10 V to -10 V.

By sampling the speech signal at 20 KHz and quantizing it with 8 bits, we can effectively capture and represent the essential characteristics of the signal. This allows for efficient storage, transmission, and processing of speech signals in various applications such as telecommunications, audio recording, and speech recognition.

In conclusion, the speech signal we discussed is band-limited to 5 KHz, sampled at a rate of 20 KHz, and quantized using 8 bits. These parameters ensure that the important information within the speech signal is accurately captured and represented. Understanding the technical aspects of speech signals is crucial for developing advanced speech processing systems and enhancing our communication technologies.

Thank you for your attention.
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Community Answer
A speech signal, band limited to 5 KHz with peak to peak between +10 V...
While using polar pulses, the minimum bandwidth required is four times the theoretical bandwidth or nyquist bandwidth.
Required BW = 4 * Nyquist BW
= 4 × 2 fm = 4 × 2 × 5 KHz = 40 KHz
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