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In an experiment, 2.4g of iron oxide on reduction with hydrogen gave 1.68 g of iron. In another experiment, 2.9 g of iron oxide gave 2.09 g of iron on reduction.Which law is illustrated from the above data?
- a)Law of constant proportions
- b)Law of multiple proportions
- c)Law of reciprocal proportions
- d)Law of conservation of mass
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
In an experiment, 2.4g of iron oxide on reduction with hydrogen gave 1...
In first experiment,
2.4 g of iron oxide gave 1.68 g of iron.
Mass of iron oxide = 2.4 g
Mass of iron = 1.68 g
Mass of oxygen = 2.4 - 1.68 = 0.72
Ratio of masses of iron and oxygen = 1.68/0.72 = 7:3
In second experiment,
Mass of iron oxide = 2.9 g
Mass of iron = 2.09 g
Mass of oxygen = 2.9 - 2.09 = 0.81
Ratio of masses of iron and oxygen = 2.09/0.81 = 7.3
The same ratio confirms that these experiments clarify Law of constant proportions.
2.4 g of iron oxide gave 1.68 g of iron.
Mass of iron oxide = 2.4 g
Mass of iron = 1.68 g
Mass of oxygen = 2.4 - 1.68 = 0.72
Ratio of masses of iron and oxygen = 1.68/0.72 = 7:3
In second experiment,
Mass of iron oxide = 2.9 g
Mass of iron = 2.09 g
Mass of oxygen = 2.9 - 2.09 = 0.81
Ratio of masses of iron and oxygen = 2.09/0.81 = 7.3
The same ratio confirms that these experiments clarify Law of constant proportions.
Most Upvoted Answer
In an experiment, 2.4g of iron oxide on reduction with hydrogen gave 1...
Law of Constant Proportions:
The law of constant proportions or the law of definite proportions states that a given chemical compound always contains the same elements in a fixed proportion by mass. This means that the ratio of the masses of the constituent elements in a compound is always the same, regardless of the source or method of preparation of the compound.
Explanation:
In the given problem, two experiments were conducted to study the reduction of iron oxide with hydrogen. The results of the experiments are as follows:
- Experiment 1: 2.4 g of iron oxide gave 1.68 g of iron on reduction with hydrogen.
- Experiment 2: 2.9 g of iron oxide gave 2.09 g of iron on reduction with hydrogen.
Now, we can calculate the mass ratio of iron and oxygen in each experiment as follows:
- Experiment 1: Mass of iron = 1.68 g, Mass of iron oxide = 2.4 g, Mass of oxygen = 2.4 g - 1.68 g = 0.72 g. Therefore, Mass ratio of iron to oxygen = 1.68 g / 0.72 g = 2.33.
- Experiment 2: Mass of iron = 2.09 g, Mass of iron oxide = 2.9 g, Mass of oxygen = 2.9 g - 2.09 g = 0.81 g. Therefore, Mass ratio of iron to oxygen = 2.09 g / 0.81 g = 2.58.
From the above calculations, we can see that the mass ratio of iron to oxygen is different in each experiment. However, the mass ratio of iron to oxygen is constant within each experiment. This means that the law of constant proportions is illustrated in this problem.
Conclusion:
The law of constant proportions is illustrated in the given problem as the mass ratio of iron to oxygen is constant within each experiment, even though the overall mass of iron oxide and the mass of iron obtained are different in each experiment.
The law of constant proportions or the law of definite proportions states that a given chemical compound always contains the same elements in a fixed proportion by mass. This means that the ratio of the masses of the constituent elements in a compound is always the same, regardless of the source or method of preparation of the compound.
Explanation:
In the given problem, two experiments were conducted to study the reduction of iron oxide with hydrogen. The results of the experiments are as follows:
- Experiment 1: 2.4 g of iron oxide gave 1.68 g of iron on reduction with hydrogen.
- Experiment 2: 2.9 g of iron oxide gave 2.09 g of iron on reduction with hydrogen.
Now, we can calculate the mass ratio of iron and oxygen in each experiment as follows:
- Experiment 1: Mass of iron = 1.68 g, Mass of iron oxide = 2.4 g, Mass of oxygen = 2.4 g - 1.68 g = 0.72 g. Therefore, Mass ratio of iron to oxygen = 1.68 g / 0.72 g = 2.33.
- Experiment 2: Mass of iron = 2.09 g, Mass of iron oxide = 2.9 g, Mass of oxygen = 2.9 g - 2.09 g = 0.81 g. Therefore, Mass ratio of iron to oxygen = 2.09 g / 0.81 g = 2.58.
From the above calculations, we can see that the mass ratio of iron to oxygen is different in each experiment. However, the mass ratio of iron to oxygen is constant within each experiment. This means that the law of constant proportions is illustrated in this problem.
Conclusion:
The law of constant proportions is illustrated in the given problem as the mass ratio of iron to oxygen is constant within each experiment, even though the overall mass of iron oxide and the mass of iron obtained are different in each experiment.
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In an experiment, 2.4g of iron oxide on reduction with hydrogen gave 1.68 g of iron. In another experiment, 2.9 g of iron oxide gave 2.09 g of iron on reduction.Which law is illustrated from the above data?a)Law of constant proportionsb)Law of multiple proportionsc)Law of reciprocal proportionsd)Law of conservation of massCorrect answer is option 'A'. Can you explain this answer?
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In an experiment, 2.4g of iron oxide on reduction with hydrogen gave 1.68 g of iron. In another experiment, 2.9 g of iron oxide gave 2.09 g of iron on reduction.Which law is illustrated from the above data?a)Law of constant proportionsb)Law of multiple proportionsc)Law of reciprocal proportionsd)Law of conservation of massCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In an experiment, 2.4g of iron oxide on reduction with hydrogen gave 1.68 g of iron. In another experiment, 2.9 g of iron oxide gave 2.09 g of iron on reduction.Which law is illustrated from the above data?a)Law of constant proportionsb)Law of multiple proportionsc)Law of reciprocal proportionsd)Law of conservation of massCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment, 2.4g of iron oxide on reduction with hydrogen gave 1.68 g of iron. In another experiment, 2.9 g of iron oxide gave 2.09 g of iron on reduction.Which law is illustrated from the above data?a)Law of constant proportionsb)Law of multiple proportionsc)Law of reciprocal proportionsd)Law of conservation of massCorrect answer is option 'A'. Can you explain this answer?.
In an experiment, 2.4g of iron oxide on reduction with hydrogen gave 1.68 g of iron. In another experiment, 2.9 g of iron oxide gave 2.09 g of iron on reduction.Which law is illustrated from the above data?a)Law of constant proportionsb)Law of multiple proportionsc)Law of reciprocal proportionsd)Law of conservation of massCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In an experiment, 2.4g of iron oxide on reduction with hydrogen gave 1.68 g of iron. In another experiment, 2.9 g of iron oxide gave 2.09 g of iron on reduction.Which law is illustrated from the above data?a)Law of constant proportionsb)Law of multiple proportionsc)Law of reciprocal proportionsd)Law of conservation of massCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment, 2.4g of iron oxide on reduction with hydrogen gave 1.68 g of iron. In another experiment, 2.9 g of iron oxide gave 2.09 g of iron on reduction.Which law is illustrated from the above data?a)Law of constant proportionsb)Law of multiple proportionsc)Law of reciprocal proportionsd)Law of conservation of massCorrect answer is option 'A'. Can you explain this answer?.
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In an experiment, 2.4g of iron oxide on reduction with hydrogen gave 1.68 g of iron. In another experiment, 2.9 g of iron oxide gave 2.09 g of iron on reduction.Which law is illustrated from the above data?a)Law of constant proportionsb)Law of multiple proportionsc)Law of reciprocal proportionsd)Law of conservation of massCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for In an experiment, 2.4g of iron oxide on reduction with hydrogen gave 1.68 g of iron. In another experiment, 2.9 g of iron oxide gave 2.09 g of iron on reduction.Which law is illustrated from the above data?a)Law of constant proportionsb)Law of multiple proportionsc)Law of reciprocal proportionsd)Law of conservation of massCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of In an experiment, 2.4g of iron oxide on reduction with hydrogen gave 1.68 g of iron. In another experiment, 2.9 g of iron oxide gave 2.09 g of iron on reduction.Which law is illustrated from the above data?a)Law of constant proportionsb)Law of multiple proportionsc)Law of reciprocal proportionsd)Law of conservation of massCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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