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An electric field of 1000 V/m is applied to an electric dipole at an angle of 45°. The value of the electric dipole moment is 10–29 C.m. What is the potential energy of the electric dipole?
  • a)
    –20 × 10–18 J
  • b)
    –7 × 10 –27 J
  • c)
    –10 × 10–29 J
  • d)
    – 9 × 10–20 J
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
An electric field of 1000 V/m is applied to an electric dipole at an ...
Potential energy of a dipole is given by
= – PE cos θ
[Whereθ = angle between dipole and perpendicular to the field]
= – (10–29) (103) cos 45°
= – 0.707 × 10–26 J = – 7 × 10–27J
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An electric field of 1000 V/m is applied to an electric dipole at an angle of 45°. The value of the electric dipole moment is 10–29 C.m. What is the potential energy of the electric dipole?a)–20 × 10–18 Jb)–7 × 10 –27 Jc)–10 × 10–29 Jd)– 9 × 10–20 JCorrect answer is option 'B'. Can you explain this answer?
Question Description
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