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A calorimeter of water equivalent 20 g contains 180 g of water at 25°C. 'm' grams of steam at 100°C is mixed in it till the temperature of the mixture is 31°C. The value of 'm' is close to (Latent heat of water = 540 cal g–1, specific heat of water = 1 cal g–1 °C–1)a)2b)4c)3.2d)2.6Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared
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A calorimeter of water equivalent 20 g contains 180 g of water at 25°C. 'm' grams of steam at 100°C is mixed in it till the temperature of the mixture is 31°C. The value of 'm' is close to (Latent heat of water = 540 cal g–1, specific heat of water = 1 cal g–1 °C–1)a)2b)4c)3.2d)2.6Correct answer is option 'A'. Can you explain this answer?, a detailed solution for A calorimeter of water equivalent 20 g contains 180 g of water at 25°C. 'm' grams of steam at 100°C is mixed in it till the temperature of the mixture is 31°C. The value of 'm' is close to (Latent heat of water = 540 cal g–1, specific heat of water = 1 cal g–1 °C–1)a)2b)4c)3.2d)2.6Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of A calorimeter of water equivalent 20 g contains 180 g of water at 25°C. 'm' grams of steam at 100°C is mixed in it till the temperature of the mixture is 31°C. The value of 'm' is close to (Latent heat of water = 540 cal g–1, specific heat of water = 1 cal g–1 °C–1)a)2b)4c)3.2d)2.6Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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