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The temperature of 50g of water has to be risen from 15°C to 85°C by using steam at 120°C. What is the amount of steam, in gms, required for the same? Sw= 1cal/ g°C, Lvap = 540cal/g, Ssteam =0.48cal/g°C.
- a)6.29g
- b)8.34g
- c)7.22g
- d)6.19g
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
The temperature of 50g of water has to be risen from 15°C to 85&de...
Heat lost by steam = Heat gained by water. Let ‘m’ be the mass of steam required.
∴ mSsteam (120-100) + mLvap + mSw (100-85) = 50Sw (85-15) The only variable is ‘m’.
On calculating it from the above equation, we get:
m = 6.19g.
∴ mSsteam (120-100) + mLvap + mSw (100-85) = 50Sw (85-15) The only variable is ‘m’.
On calculating it from the above equation, we get:
m = 6.19g.
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Community Answer
The temperature of 50g of water has to be risen from 15°C to 85&de...
Given data:
- Mass of water (m) = 50g
- Initial temperature of water (Ti) = 15°C
- Final temperature of water (Tf) = 85°C
- Temperature of steam (Ts) = 120°C
- Specific heat capacity of water (Sw) = 1 cal/g°C
- Latent heat of vaporization (Lvap) = 540 cal/g
- Specific heat capacity of steam (Ssteam) = 0.48 cal/g°C
Calculations:
1. Heat required to raise the temperature of water from 15°C to 100°C:
\(Q = m \times Sw \times (Tf - Ti)\)
\(Q = 50 \times 1 \times (85 - 15)\)
\(Q = 50 \times 70\)
\(Q = 3500 cal\)
2. Heat required to convert water at 100°C to steam at 120°C:
\(Q = m \times Lvap\)
\(3500 = m \times 540\)
\(m = \frac{3500}{540}\)
\(m ≈ 6.48g\)
3. Heat required to raise the temperature of steam from 100°C to 120°C:
\(Q = m \times Ssteam \times (Ts - 100)\)
\(Q = 6.48 \times 0.48 \times (120 - 100)\)
\(Q = 6.48 \times 0.48 \times 20\)
\(Q = 6.19g\)
Therefore, the amount of steam required to raise the temperature of 50g of water from 15°C to 85°C is approximately 6.19g. Option D is the correct answer.
- Mass of water (m) = 50g
- Initial temperature of water (Ti) = 15°C
- Final temperature of water (Tf) = 85°C
- Temperature of steam (Ts) = 120°C
- Specific heat capacity of water (Sw) = 1 cal/g°C
- Latent heat of vaporization (Lvap) = 540 cal/g
- Specific heat capacity of steam (Ssteam) = 0.48 cal/g°C
Calculations:
1. Heat required to raise the temperature of water from 15°C to 100°C:
\(Q = m \times Sw \times (Tf - Ti)\)
\(Q = 50 \times 1 \times (85 - 15)\)
\(Q = 50 \times 70\)
\(Q = 3500 cal\)
2. Heat required to convert water at 100°C to steam at 120°C:
\(Q = m \times Lvap\)
\(3500 = m \times 540\)
\(m = \frac{3500}{540}\)
\(m ≈ 6.48g\)
3. Heat required to raise the temperature of steam from 100°C to 120°C:
\(Q = m \times Ssteam \times (Ts - 100)\)
\(Q = 6.48 \times 0.48 \times (120 - 100)\)
\(Q = 6.48 \times 0.48 \times 20\)
\(Q = 6.19g\)
Therefore, the amount of steam required to raise the temperature of 50g of water from 15°C to 85°C is approximately 6.19g. Option D is the correct answer.
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The temperature of 50g of water has to be risen from 15°C to 85°C by using steam at 120°C. What is the amount of steam, in gms, required for the same? Sw= 1cal/ g°C, Lvap= 540cal/g, Ssteam=0.48cal/g°C.a)6.29gb)8.34gc)7.22gd)6.19gCorrect answer is option 'D'. Can you explain this answer?
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The temperature of 50g of water has to be risen from 15°C to 85°C by using steam at 120°C. What is the amount of steam, in gms, required for the same? Sw= 1cal/ g°C, Lvap= 540cal/g, Ssteam=0.48cal/g°C.a)6.29gb)8.34gc)7.22gd)6.19gCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The temperature of 50g of water has to be risen from 15°C to 85°C by using steam at 120°C. What is the amount of steam, in gms, required for the same? Sw= 1cal/ g°C, Lvap= 540cal/g, Ssteam=0.48cal/g°C.a)6.29gb)8.34gc)7.22gd)6.19gCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The temperature of 50g of water has to be risen from 15°C to 85°C by using steam at 120°C. What is the amount of steam, in gms, required for the same? Sw= 1cal/ g°C, Lvap= 540cal/g, Ssteam=0.48cal/g°C.a)6.29gb)8.34gc)7.22gd)6.19gCorrect answer is option 'D'. Can you explain this answer?.
The temperature of 50g of water has to be risen from 15°C to 85°C by using steam at 120°C. What is the amount of steam, in gms, required for the same? Sw= 1cal/ g°C, Lvap= 540cal/g, Ssteam=0.48cal/g°C.a)6.29gb)8.34gc)7.22gd)6.19gCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The temperature of 50g of water has to be risen from 15°C to 85°C by using steam at 120°C. What is the amount of steam, in gms, required for the same? Sw= 1cal/ g°C, Lvap= 540cal/g, Ssteam=0.48cal/g°C.a)6.29gb)8.34gc)7.22gd)6.19gCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The temperature of 50g of water has to be risen from 15°C to 85°C by using steam at 120°C. What is the amount of steam, in gms, required for the same? Sw= 1cal/ g°C, Lvap= 540cal/g, Ssteam=0.48cal/g°C.a)6.29gb)8.34gc)7.22gd)6.19gCorrect answer is option 'D'. Can you explain this answer?.
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