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Vapour pressure (in torr) of an ideal solution of two liquids A and B is given by : P = 52XA + 114 where XA is the mole fraction of A in the mixture.
The vapour pressure (in torr) of equimolar mixture of the two liquids will be :
  • a)
    166
  • b)
    83
  • c)
    140
  • d)
    280
Correct answer is option 'C'. Can you explain this answer?
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Given Information:
The formula for the vapor pressure of an ideal solution of two liquids A and B is given by: P = 52XA + 114, where XA is the mole fraction of A in the mixture.

Equimolar Mixture:
- In an equimolar mixture, the mole fraction of A (XA) is equal to the mole fraction of B.
- Therefore, XA = XB = 0.5 (since it is an equimolar mixture).

Calculating Vapor Pressure:
- Substituting XA = 0.5 into the formula P = 52XA + 114:
P = 52(0.5) + 114
P = 26 + 114
P = 140 torr
Therefore, the vapor pressure of the equimolar mixture of the two liquids is 140 torr, which corresponds to option 'C'.
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Vapour pressure (in torr) of an ideal solution of two liquids A and B is given by : P = 52XA + 114 where XA is the mole fraction of A in the mixture.The vapour pressure (in torr) of equimolar mixture of the two liquids will be :a)166b)83c)140d)280Correct answer is option 'C'. Can you explain this answer?
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