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Vapour pressure (in torr) of an ideal solution of two liquids A and B is given by: P = 52XA +114 where XA is the mole fraction of A  in the mixture.The vapour pressure (in torr) of equimolar mixture of the two liquids will be:
  • a)
    166
  • b)
    83
  • c)
    140
  • d)
    280
Correct answer is option 'C'. Can you explain this answer?
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Vapour pressure (in torr) of an ideal solution of two liquids A and B ...
Total V.P.,

Thus, 
 or Pº= 166 torr
Hence 
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Vapour pressure (in torr) of an ideal solution of two liquids A and B ...
Given: P = 52XA 114 (where XA is the mole fraction of A in the mixture)

To find: Vapour pressure (in torr) of equimolar mixture of the two liquids

Solution:

Let's assume that the equimolar mixture contains x moles of A and x moles of B.

Mole fraction of A in the mixture, XA = x / (x + x) = 0.5

Mole fraction of B in the mixture, XB = 0.5

Using the given formula, we can calculate the vapour pressure of the mixture:

P = 52XA + 114
P = 52(0.5) + 114
P = 26 + 114
P = 140 torr

Therefore, the vapour pressure (in torr) of equimolar mixture of the two liquids is 140 (option C).
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Vapour pressure (in torr) of an ideal solution of two liquids A and B ...
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Vapour pressure (in torr) of an ideal solution of two liquids A and B is given by: P = 52XA +114 where XA is the mole fraction of A in the mixture.The vapour pressure (in torr) of equimolar mixture of the two liquids will be:a)166b)83c)140d)280Correct answer is option 'C'. Can you explain this answer?
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