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In A.C. circuit in which inductance and capacitance are joined in series, current is found to be maximum when the value of inductance is 0.5 H and the value of capacitance is 8 μF. The angular frequency of applied alternating voltage will be
  • a)
    400 Hz
  • b)
    5000 Hz
  • c)
    2 × 105 Hz
  • d)
    500 Hz
Correct answer is option 'D'. Can you explain this answer?
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In A.C. circuit in which inductance and capacitance are joined in ser...
Current is max at resonance condition
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In A.C. circuit in which inductance and capacitance are joined in ser...
The angular frequency of the applied alternating voltage can be calculated using the formula:
ω = 1/√(LC)
Where,
ω = angular frequency
L = inductance (0.5 H)
C = capacitance (8 μF = 8 × 10^-6 F)
Given values:
L = 0.5 H
C = 8 × 10^-6 F
Let's calculate the angular frequency:
ω = 1/√(0.5 × 8 × 10^-6)
ω = 1/√(4 × 10^-6)
ω = 1/(2 × 10^-3)
ω = 500 Hz
Therefore, the angular frequency of the applied alternating voltage is 500 Hz, which corresponds to option 'D'.
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