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A coil has an inductance of 2. 2/pai H. and is joined in series with a resistance of 220 W. when an alternating emf of 220 at 50 cps is applied to it, then the wattless component of the rms current in the circuit is. ??? ans is 0. 5 A.?
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A coil has an inductance of 2. 2/pai H. and is joined in series with a...
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A coil has an inductance of 2. 2/pai H. and is joined in series with a...
Given data:
- Inductance of the coil (L) = 2.2/π H
- Resistance (R) = 220 Ω
- Applied alternating EMF (E) = 220 V
- Frequency (f) = 50 Hz
To find:
Wattless component of the rms current in the circuit.
Solution:
Step 1: Calculation of Reactance (X)
Reactance is the opposition offered by an inductor to the flow of alternating current and is given by the formula X = 2πfL, where f is the frequency and L is the inductance.
Given:
Inductance (L) = 2.2/π H
Frequency (f) = 50 Hz
Using the formula, we can calculate the reactance (X):
X = 2πfL
X = 2 * 3.1416 * 50 * (2.2/π)
X = 220 Ω
Step 2: Calculation of Impedance (Z)
Impedance is the total effective resistance offered by a circuit to alternating current and is given by the formula Z = √(R^2 + X^2), where R is the resistance and X is the reactance.
Given:
Resistance (R) = 220 Ω
Reactance (X) = 220 Ω
Using the formula, we can calculate the impedance (Z):
Z = √(R^2 + X^2)
Z = √((220^2) + (220^2))
Z = √(48400 + 48400)
Z = √96800
Z = 310 Ω
Step 3: Calculation of Current (I)
Current in the circuit is given by the formula I = E/Z, where E is the applied EMF and Z is the impedance.
Given:
Applied EMF (E) = 220 V
Impedance (Z) = 310 Ω
Using the formula, we can calculate the current (I):
I = E/Z
I = 220/310
I ≈ 0.7097 A
Step 4: Calculation of Wattless Component of Current (Iw)
Wattless component of current is given by the formula Iw = √(I^2 - (E/R)^2), where I is the current, E is the applied EMF, and R is the resistance.
Given:
Current (I) ≈ 0.7097 A
Applied EMF (E) = 220 V
Resistance (R) = 220 Ω
Using the formula, we can calculate the wattless component of current (Iw):
Iw = √(I^2 - (E/R)^2)
Iw = √((0.7097^2) - ((220/220)^2))
Iw = √(0.5038 - 1)
Iw = √(-0.4962)
Iw ≈ 0.5 A
Therefore, the wattless component of the rms current in the circuit is approximately 0.5 A.
- Inductance of the coil (L) = 2.2/π H
- Resistance (R) = 220 Ω
- Applied alternating EMF (E) = 220 V
- Frequency (f) = 50 Hz
To find:
Wattless component of the rms current in the circuit.
Solution:
Step 1: Calculation of Reactance (X)
Reactance is the opposition offered by an inductor to the flow of alternating current and is given by the formula X = 2πfL, where f is the frequency and L is the inductance.
Given:
Inductance (L) = 2.2/π H
Frequency (f) = 50 Hz
Using the formula, we can calculate the reactance (X):
X = 2πfL
X = 2 * 3.1416 * 50 * (2.2/π)
X = 220 Ω
Step 2: Calculation of Impedance (Z)
Impedance is the total effective resistance offered by a circuit to alternating current and is given by the formula Z = √(R^2 + X^2), where R is the resistance and X is the reactance.
Given:
Resistance (R) = 220 Ω
Reactance (X) = 220 Ω
Using the formula, we can calculate the impedance (Z):
Z = √(R^2 + X^2)
Z = √((220^2) + (220^2))
Z = √(48400 + 48400)
Z = √96800
Z = 310 Ω
Step 3: Calculation of Current (I)
Current in the circuit is given by the formula I = E/Z, where E is the applied EMF and Z is the impedance.
Given:
Applied EMF (E) = 220 V
Impedance (Z) = 310 Ω
Using the formula, we can calculate the current (I):
I = E/Z
I = 220/310
I ≈ 0.7097 A
Step 4: Calculation of Wattless Component of Current (Iw)
Wattless component of current is given by the formula Iw = √(I^2 - (E/R)^2), where I is the current, E is the applied EMF, and R is the resistance.
Given:
Current (I) ≈ 0.7097 A
Applied EMF (E) = 220 V
Resistance (R) = 220 Ω
Using the formula, we can calculate the wattless component of current (Iw):
Iw = √(I^2 - (E/R)^2)
Iw = √((0.7097^2) - ((220/220)^2))
Iw = √(0.5038 - 1)
Iw = √(-0.4962)
Iw ≈ 0.5 A
Therefore, the wattless component of the rms current in the circuit is approximately 0.5 A.
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A coil has an inductance of 2. 2/pai H. and is joined in series with a resistance of 220 W. when an alternating emf of 220 at 50 cps is applied to it, then the wattless component of the rms current in the circuit is. ??? ans is 0. 5 A.?
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A coil has an inductance of 2. 2/pai H. and is joined in series with a resistance of 220 W. when an alternating emf of 220 at 50 cps is applied to it, then the wattless component of the rms current in the circuit is. ??? ans is 0. 5 A.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A coil has an inductance of 2. 2/pai H. and is joined in series with a resistance of 220 W. when an alternating emf of 220 at 50 cps is applied to it, then the wattless component of the rms current in the circuit is. ??? ans is 0. 5 A.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A coil has an inductance of 2. 2/pai H. and is joined in series with a resistance of 220 W. when an alternating emf of 220 at 50 cps is applied to it, then the wattless component of the rms current in the circuit is. ??? ans is 0. 5 A.?.
A coil has an inductance of 2. 2/pai H. and is joined in series with a resistance of 220 W. when an alternating emf of 220 at 50 cps is applied to it, then the wattless component of the rms current in the circuit is. ??? ans is 0. 5 A.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A coil has an inductance of 2. 2/pai H. and is joined in series with a resistance of 220 W. when an alternating emf of 220 at 50 cps is applied to it, then the wattless component of the rms current in the circuit is. ??? ans is 0. 5 A.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A coil has an inductance of 2. 2/pai H. and is joined in series with a resistance of 220 W. when an alternating emf of 220 at 50 cps is applied to it, then the wattless component of the rms current in the circuit is. ??? ans is 0. 5 A.?.
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A coil has an inductance of 2. 2/pai H. and is joined in series with a resistance of 220 W. when an alternating emf of 220 at 50 cps is applied to it, then the wattless component of the rms current in the circuit is. ??? ans is 0. 5 A.?, a detailed solution for A coil has an inductance of 2. 2/pai H. and is joined in series with a resistance of 220 W. when an alternating emf of 220 at 50 cps is applied to it, then the wattless component of the rms current in the circuit is. ??? ans is 0. 5 A.? has been provided alongside types of A coil has an inductance of 2. 2/pai H. and is joined in series with a resistance of 220 W. when an alternating emf of 220 at 50 cps is applied to it, then the wattless component of the rms current in the circuit is. ??? ans is 0. 5 A.? theory, EduRev gives you an
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