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Sucrose in water is dextro-rotatory, [α]D= + 66.4º.
When boiled with dilute HCl, the solution becomes leavo-rotatory, [α]D = –20º. In this process the sucrose molecule breaks into
- a)L-glucose + D-fructose
- b)L-glucose + L-fructose
- c)D-glucose + D-fructose
- d)D-glucose + L-fructose
Correct answer is option 'C'. Can you explain this answer?
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Sucrose in water is dextro-rotatory, [α]D= + 66.4º.When boiled with d...
Sucrose hydrolysis in dilute HCl
Sucrose is a disaccharide composed of glucose and fructose units linked by a glycosidic bond. When sucrose is boiled with dilute HCl, it undergoes hydrolysis, breaking down into its constituent monosaccharides.
Change in optical activity
Sucrose in water is dextro-rotatory, meaning it rotates plane-polarized light to the right. The specific rotation of sucrose in water is α]D= 66.4º. However, when sucrose is boiled with dilute HCl, the solution becomes leavo-rotatory, meaning it rotates plane-polarized light to the left. The specific rotation of the hydrolyzed solution is [α]D = –20º.
Explanation
Sucrose hydrolysis with dilute HCl results in the formation of equimolar amounts of glucose and fructose. Both glucose and fructose are optically active compounds, but they have different specific rotations. Glucose has a specific rotation of [α]D = +52.5º and is dextro-rotatory, while fructose has a specific rotation of [α]D = –92.4º and is leavo-rotatory.
The change in optical activity observed during sucrose hydrolysis is due to the different specific rotations of glucose and fructose. The presence of both glucose and fructose in the hydrolyzed solution results in a net change in optical activity, leading to a leavo-rotatory solution.
Conclusion
Sucrose hydrolysis with dilute HCl results in the formation of equimolar amounts of glucose and fructose. The change in optical activity observed during this process is due to the different specific rotations of glucose and fructose. The hydrolyzed solution is leavo-rotatory, with a specific rotation of [α]D = –20º.
Sucrose is a disaccharide composed of glucose and fructose units linked by a glycosidic bond. When sucrose is boiled with dilute HCl, it undergoes hydrolysis, breaking down into its constituent monosaccharides.
Change in optical activity
Sucrose in water is dextro-rotatory, meaning it rotates plane-polarized light to the right. The specific rotation of sucrose in water is α]D= 66.4º. However, when sucrose is boiled with dilute HCl, the solution becomes leavo-rotatory, meaning it rotates plane-polarized light to the left. The specific rotation of the hydrolyzed solution is [α]D = –20º.
Explanation
Sucrose hydrolysis with dilute HCl results in the formation of equimolar amounts of glucose and fructose. Both glucose and fructose are optically active compounds, but they have different specific rotations. Glucose has a specific rotation of [α]D = +52.5º and is dextro-rotatory, while fructose has a specific rotation of [α]D = –92.4º and is leavo-rotatory.
The change in optical activity observed during sucrose hydrolysis is due to the different specific rotations of glucose and fructose. The presence of both glucose and fructose in the hydrolyzed solution results in a net change in optical activity, leading to a leavo-rotatory solution.
Conclusion
Sucrose hydrolysis with dilute HCl results in the formation of equimolar amounts of glucose and fructose. The change in optical activity observed during this process is due to the different specific rotations of glucose and fructose. The hydrolyzed solution is leavo-rotatory, with a specific rotation of [α]D = –20º.
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Sucrose in water is dextro-rotatory, [α]D= + 66.4º.When boiled with d...
The hydrolysis of sucrose by boiling with mineral acid or by enzyme invertase or sucrase produces a mixture of equal molecules of D (+)-glucose and D (-) -Fructose.
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Sucrose in water is dextro-rotatory, [α]D= + 66.4º.When boiled with dilute HCl, the solution becomes leavo-rotatory, [α]D = –20º. In this process the sucrose molecule breaks intoa)L-glucose + D-fructoseb)L-glucose + L-fructosec)D-glucose + D-fructosed)D-glucose + L-fructoseCorrect answer is option 'C'. Can you explain this answer?
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Sucrose in water is dextro-rotatory, [α]D= + 66.4º.When boiled with dilute HCl, the solution becomes leavo-rotatory, [α]D = –20º. In this process the sucrose molecule breaks intoa)L-glucose + D-fructoseb)L-glucose + L-fructosec)D-glucose + D-fructosed)D-glucose + L-fructoseCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Sucrose in water is dextro-rotatory, [α]D= + 66.4º.When boiled with dilute HCl, the solution becomes leavo-rotatory, [α]D = –20º. In this process the sucrose molecule breaks intoa)L-glucose + D-fructoseb)L-glucose + L-fructosec)D-glucose + D-fructosed)D-glucose + L-fructoseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Sucrose in water is dextro-rotatory, [α]D= + 66.4º.When boiled with dilute HCl, the solution becomes leavo-rotatory, [α]D = –20º. In this process the sucrose molecule breaks intoa)L-glucose + D-fructoseb)L-glucose + L-fructosec)D-glucose + D-fructosed)D-glucose + L-fructoseCorrect answer is option 'C'. Can you explain this answer?.
Sucrose in water is dextro-rotatory, [α]D= + 66.4º.When boiled with dilute HCl, the solution becomes leavo-rotatory, [α]D = –20º. In this process the sucrose molecule breaks intoa)L-glucose + D-fructoseb)L-glucose + L-fructosec)D-glucose + D-fructosed)D-glucose + L-fructoseCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Sucrose in water is dextro-rotatory, [α]D= + 66.4º.When boiled with dilute HCl, the solution becomes leavo-rotatory, [α]D = –20º. In this process the sucrose molecule breaks intoa)L-glucose + D-fructoseb)L-glucose + L-fructosec)D-glucose + D-fructosed)D-glucose + L-fructoseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Sucrose in water is dextro-rotatory, [α]D= + 66.4º.When boiled with dilute HCl, the solution becomes leavo-rotatory, [α]D = –20º. In this process the sucrose molecule breaks intoa)L-glucose + D-fructoseb)L-glucose + L-fructosec)D-glucose + D-fructosed)D-glucose + L-fructoseCorrect answer is option 'C'. Can you explain this answer?.
Solutions for Sucrose in water is dextro-rotatory, [α]D= + 66.4º.When boiled with dilute HCl, the solution becomes leavo-rotatory, [α]D = –20º. In this process the sucrose molecule breaks intoa)L-glucose + D-fructoseb)L-glucose + L-fructosec)D-glucose + D-fructosed)D-glucose + L-fructoseCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
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