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The group of bits 11001 is serially shifted (right-most bit first) into a 5-bit parallel output shift register with an initial state 01110. After three clock pulses, the register contains ________
- a)01110
- b)00001
- c)00101
- d)00110
Correct answer is option 'C'. Can you explain this answer?
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The group of bits 11001 is serially shifted (right-most bit first) int...
Given Information:
- The group of bits 11001 is serially shifted (right-most bit first) into a 5-bit parallel output shift register.
- The register has an initial state of 01110.
- The register shifts on every clock pulse.
To Find:
- The state of the register after three clock pulses.
Solution:
- The given group of bits, 11001, is serially shifted into the register with an initial state of 01110.
- The right-most bit of the group of bits is shifted into the first bit of the register.
- After the first clock pulse, the state of the register becomes 10111 (the first bit is replaced by 1, and the other bits are shifted to the right).
- After the second clock pulse, the state of the register becomes 11011 (the first bit is replaced by 1, and the other bits are shifted to the right).
- After the third clock pulse, the state of the register becomes 00101 (the first bit is replaced by 0, and the other bits are shifted to the right).
Therefore, the correct answer is option C, 00101.
- The group of bits 11001 is serially shifted (right-most bit first) into a 5-bit parallel output shift register.
- The register has an initial state of 01110.
- The register shifts on every clock pulse.
To Find:
- The state of the register after three clock pulses.
Solution:
- The given group of bits, 11001, is serially shifted into the register with an initial state of 01110.
- The right-most bit of the group of bits is shifted into the first bit of the register.
- After the first clock pulse, the state of the register becomes 10111 (the first bit is replaced by 1, and the other bits are shifted to the right).
- After the second clock pulse, the state of the register becomes 11011 (the first bit is replaced by 1, and the other bits are shifted to the right).
- After the third clock pulse, the state of the register becomes 00101 (the first bit is replaced by 0, and the other bits are shifted to the right).
Therefore, the correct answer is option C, 00101.
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Community Answer
The group of bits 11001 is serially shifted (right-most bit first) int...
LSB bit is inverted and feed back to MSB:
01110->initial
10111->first clock pulse
01011->second
00101->third.
01110->initial
10111->first clock pulse
01011->second
00101->third.
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