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Acetone has a vapour pressure of 185.2 mm Hg and ether 443.5 mm Hg at 20ºC. For a liquid mixture of acetone and ether containing 0.457 mole fraction of acetone, the partial pressure of ether is:
- a)218.8 mm
- b)240.8 mm
- c)318.8 mm
- d)381.8 mm
Correct answer is option 'B'. Can you explain this answer?
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Acetone has a vapour pressure of 185.2 mm Hg and ether 443.5 mm Hg at...
Given:
Acetone:
- Vapour pressure: 185.2 mm Hg
Ether:
- Vapour pressure: 443.5 mm Hg
- Mole fraction of acetone in the mixture: 0.457
To find:
Partial pressure of ether in the mixture
Solution:
The partial pressure of a component in a mixture can be calculated using Raoult's law, which states that the partial pressure of a component is equal to the product of its mole fraction in the mixture and its vapour pressure at that temperature.
Step 1: Calculate the mole fraction of ether
Since the mole fraction of acetone is given as 0.457, the mole fraction of ether can be calculated as:
Mole fraction of ether = 1 - Mole fraction of acetone
= 1 - 0.457
= 0.543
Step 2: Calculate the partial pressure of ether
Using Raoult's law, the partial pressure of ether can be calculated as:
Partial pressure of ether = Mole fraction of ether * Vapour pressure of ether
= 0.543 * 443.5 mm Hg
= 240.8 mm Hg
Therefore, the partial pressure of ether in the liquid mixture is 240.8 mm Hg.
Answer:
Option B) 240.8 mm
Acetone:
- Vapour pressure: 185.2 mm Hg
Ether:
- Vapour pressure: 443.5 mm Hg
- Mole fraction of acetone in the mixture: 0.457
To find:
Partial pressure of ether in the mixture
Solution:
The partial pressure of a component in a mixture can be calculated using Raoult's law, which states that the partial pressure of a component is equal to the product of its mole fraction in the mixture and its vapour pressure at that temperature.
Step 1: Calculate the mole fraction of ether
Since the mole fraction of acetone is given as 0.457, the mole fraction of ether can be calculated as:
Mole fraction of ether = 1 - Mole fraction of acetone
= 1 - 0.457
= 0.543
Step 2: Calculate the partial pressure of ether
Using Raoult's law, the partial pressure of ether can be calculated as:
Partial pressure of ether = Mole fraction of ether * Vapour pressure of ether
= 0.543 * 443.5 mm Hg
= 240.8 mm Hg
Therefore, the partial pressure of ether in the liquid mixture is 240.8 mm Hg.
Answer:
Option B) 240.8 mm
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Community Answer
Acetone has a vapour pressure of 185.2 mm Hg and ether 443.5 mm Hg at...
Mole fraction of ether in the liquid mixture = (1 – 0.457) = 0.543
Partial pressure of ether = 0.543 ×443.5 = 240.78 mm
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Acetone has a vapour pressure of 185.2 mm Hg and ether 443.5 mm Hg at 20ºC. For a liquid mixture of acetone and ether containing 0.457 mole fraction of acetone, the partial pressure of ether is:a)218.8 mmb)240.8 mmc)318.8 mmd)381.8 mmCorrect answer is option 'B'. Can you explain this answer?
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Acetone has a vapour pressure of 185.2 mm Hg and ether 443.5 mm Hg at 20ºC. For a liquid mixture of acetone and ether containing 0.457 mole fraction of acetone, the partial pressure of ether is:a)218.8 mmb)240.8 mmc)318.8 mmd)381.8 mmCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Acetone has a vapour pressure of 185.2 mm Hg and ether 443.5 mm Hg at 20ºC. For a liquid mixture of acetone and ether containing 0.457 mole fraction of acetone, the partial pressure of ether is:a)218.8 mmb)240.8 mmc)318.8 mmd)381.8 mmCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Acetone has a vapour pressure of 185.2 mm Hg and ether 443.5 mm Hg at 20ºC. For a liquid mixture of acetone and ether containing 0.457 mole fraction of acetone, the partial pressure of ether is:a)218.8 mmb)240.8 mmc)318.8 mmd)381.8 mmCorrect answer is option 'B'. Can you explain this answer?.
Acetone has a vapour pressure of 185.2 mm Hg and ether 443.5 mm Hg at 20ºC. For a liquid mixture of acetone and ether containing 0.457 mole fraction of acetone, the partial pressure of ether is:a)218.8 mmb)240.8 mmc)318.8 mmd)381.8 mmCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Acetone has a vapour pressure of 185.2 mm Hg and ether 443.5 mm Hg at 20ºC. For a liquid mixture of acetone and ether containing 0.457 mole fraction of acetone, the partial pressure of ether is:a)218.8 mmb)240.8 mmc)318.8 mmd)381.8 mmCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Acetone has a vapour pressure of 185.2 mm Hg and ether 443.5 mm Hg at 20ºC. For a liquid mixture of acetone and ether containing 0.457 mole fraction of acetone, the partial pressure of ether is:a)218.8 mmb)240.8 mmc)318.8 mmd)381.8 mmCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Acetone has a vapour pressure of 185.2 mm Hg and ether 443.5 mm Hg at 20ºC. For a liquid mixture of acetone and ether containing 0.457 mole fraction of acetone, the partial pressure of ether is:a)218.8 mmb)240.8 mmc)318.8 mmd)381.8 mmCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
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Acetone has a vapour pressure of 185.2 mm Hg and ether 443.5 mm Hg at 20ºC. For a liquid mixture of acetone and ether containing 0.457 mole fraction of acetone, the partial pressure of ether is:a)218.8 mmb)240.8 mmc)318.8 mmd)381.8 mmCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Acetone has a vapour pressure of 185.2 mm Hg and ether 443.5 mm Hg at 20ºC. For a liquid mixture of acetone and ether containing 0.457 mole fraction of acetone, the partial pressure of ether is:a)218.8 mmb)240.8 mmc)318.8 mmd)381.8 mmCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Acetone has a vapour pressure of 185.2 mm Hg and ether 443.5 mm Hg at 20ºC. For a liquid mixture of acetone and ether containing 0.457 mole fraction of acetone, the partial pressure of ether is:a)218.8 mmb)240.8 mmc)318.8 mmd)381.8 mmCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Acetone has a vapour pressure of 185.2 mm Hg and ether 443.5 mm Hg at 20ºC. For a liquid mixture of acetone and ether containing 0.457 mole fraction of acetone, the partial pressure of ether is:a)218.8 mmb)240.8 mmc)318.8 mmd)381.8 mmCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.
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