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A double-slit apparatus is immersed in a liquid of refractive index 1.33. It has slit separation of 1 mm and distance between the plane of slits and the screen is 1.33 m. The slits are illuminated by a parallel beam of light whose wavelength in air is 6300 Å. What is the fringe width?
  • a)
    (1.33 × 0.630) mm
  • b)
    0.63/1.33 mm
  • c)
    0.63/(1.33)2 mm
  • d)
    0.63 mm
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A double-slit apparatus is immersed in a liquid of refractive index 1...
To calculate the fringe width, we can use the formula:

β = λD / d

Where,
β = fringe width
λ = wavelength of light in the medium
D = distance between the plane of slits and the screen
d = slit separation

Given:
λ in air = 6300 Å (angstroms)
n = refractive index of the liquid = 1.33
D = 1.33 m
d = 1 mm = 0.001 m

First, we need to find the wavelength of light in the liquid medium using the refractive index:

λ' = λ / n

Substituting the given values, we get:

λ' = 6300 Å / 1.33 = 4736.09 Å

Now, we convert this wavelength from angstroms to meters:

λ' = 4736.09 Å x 10^-10 m/Å = 4.73609 x 10^-7 m

Now, we can calculate the fringe width using the formula:

β = λ'D / d

Substituting the values, we get:

β = (4.73609 x 10^-7 m) x (1.33 m) / (0.001 m)

Simplifying the expression, we get:

β = 6.313 mm

Therefore, the fringe width is 0.63 mm (option D).

Free Test
Community Answer
A double-slit apparatus is immersed in a liquid of refractive index 1...
Wavelength in air is λa = 6000 Å. Let its speed in air be va. When the apparatus is immersed in a liquid the frequency of the wave remains unchanged but its wavelength and speed both will change. Let λl be the wavelength and vl be the speed in the liquid.
Since v = vλ, we have
(c is the speed of light in vacuum). Now the refractive index of a medium is n = c/v.
Hence,
Given λa = 6000 Å and nl = 4/3.
Therefore
Hence the fringe width in liquid will be
The fringe width in liquid is
where is the fringe width in air.
Thus
= 0.63 × 10-3 m = 0.63 mm
Hence the correct choice is (4).
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A double-slit apparatus is immersed in a liquid of refractive index 1.33. It has slit separation of 1 mm and distance between the plane of slits and the screen is 1.33 m. The slits are illuminated by a parallel beam of light whose wavelength in air is 6300 Å. What is the fringe width?a)(1.33 × 0.630) mmb)0.63/1.33 mmc)0.63/(1.33)2 mmd)0.63 mmCorrect answer is option 'D'. Can you explain this answer?
Question Description
A double-slit apparatus is immersed in a liquid of refractive index 1.33. It has slit separation of 1 mm and distance between the plane of slits and the screen is 1.33 m. The slits are illuminated by a parallel beam of light whose wavelength in air is 6300 Å. What is the fringe width?a)(1.33 × 0.630) mmb)0.63/1.33 mmc)0.63/(1.33)2 mmd)0.63 mmCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A double-slit apparatus is immersed in a liquid of refractive index 1.33. It has slit separation of 1 mm and distance between the plane of slits and the screen is 1.33 m. The slits are illuminated by a parallel beam of light whose wavelength in air is 6300 Å. What is the fringe width?a)(1.33 × 0.630) mmb)0.63/1.33 mmc)0.63/(1.33)2 mmd)0.63 mmCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A double-slit apparatus is immersed in a liquid of refractive index 1.33. It has slit separation of 1 mm and distance between the plane of slits and the screen is 1.33 m. The slits are illuminated by a parallel beam of light whose wavelength in air is 6300 Å. What is the fringe width?a)(1.33 × 0.630) mmb)0.63/1.33 mmc)0.63/(1.33)2 mmd)0.63 mmCorrect answer is option 'D'. Can you explain this answer?.
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