NEET Exam > NEET Questions > A particle of mass m carrying a positive cha...
Start Learning for Free
A particle of mass m carrying a positive charge q moves simple harmonically along x-axis under the action of a varying electric field E directed along x-axis. The motion of the particle is confined between x = 0 and x = 2l. The angular frequency of the motion is ω. Then, which of the following is correct?
- a)qE = - mω2(x - l)
- b)qE = mω2(x - l)
- c)Electric field to the right of origin is directed along +ve x-axis for all values of x
- d)Electric field to the right of origin is directed along -ve x-axis for all values of x
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A particle of mass m carrying a positive charge q moves simple harmon...
Explanation:
Simple Harmonic Motion (SHM) Equation:
- In SHM, the acceleration of a particle is directly proportional to its displacement from the mean position and is always directed towards the mean position.
- The equation of motion for a particle undergoing SHM is given by: a = -ω^2x, where a is the acceleration and x is the displacement from the mean position.
Relation with Electric Field:
- In the given scenario, the particle is under the influence of a varying electric field E directed along the x-axis.
- The force experienced by the particle due to the electric field is given by: F = qE, where q is the charge of the particle.
- Equating this force to the mass times acceleration (F = ma), we get: qE = -mω^2x
Confined Motion:
- The motion of the particle is confined between x = 0 and x = 2l.
- The mean position can be taken as x = l (midway between 0 and 2l).
Correct Option:
- The correct option is: qE = - mω^2(x - l).
- This equation represents the relationship between the charge q, electric field E, mass m, angular frequency ω, and displacement x from the mean position l.
Therefore, option A, qE = - mω^2(x - l), is the correct choice as it accurately reflects the dynamics of the particle undergoing simple harmonic motion under the influence of a varying electric field.
Simple Harmonic Motion (SHM) Equation:
- In SHM, the acceleration of a particle is directly proportional to its displacement from the mean position and is always directed towards the mean position.
- The equation of motion for a particle undergoing SHM is given by: a = -ω^2x, where a is the acceleration and x is the displacement from the mean position.
Relation with Electric Field:
- In the given scenario, the particle is under the influence of a varying electric field E directed along the x-axis.
- The force experienced by the particle due to the electric field is given by: F = qE, where q is the charge of the particle.
- Equating this force to the mass times acceleration (F = ma), we get: qE = -mω^2x
Confined Motion:
- The motion of the particle is confined between x = 0 and x = 2l.
- The mean position can be taken as x = l (midway between 0 and 2l).
Correct Option:
- The correct option is: qE = - mω^2(x - l).
- This equation represents the relationship between the charge q, electric field E, mass m, angular frequency ω, and displacement x from the mean position l.
Therefore, option A, qE = - mω^2(x - l), is the correct choice as it accurately reflects the dynamics of the particle undergoing simple harmonic motion under the influence of a varying electric field.
Free Test
FREE
| Start Free Test |
Community Answer
A particle of mass m carrying a positive charge q moves simple harmon...
Mean position: x = l
F = −k(x − ℓ) ⇒ where k = mω2
or qE = −mω2(x − ℓ) ⇒ At x = ℓ, E = 0
To the right of x = ℓ,E is −ve, so towards left and to the left of x = ℓ E is +ve.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Top Courses for NEETView all
A particle of mass m carrying a positive charge q moves simple harmonically along x-axis under the action of a varying electric field E directed along x-axis. The motion of the particle is confined between x = 0 and x = 2l. The angular frequency of the motion is ω. Then, which of the following is correct?a)qE = - mω2(x - l)b)qE = mω2(x - l)c)Electric field to the right of origin is directed along +ve x-axis for all values of xd)Electric field to the right of origin is directed along -ve x-axis for all values of xCorrect answer is option 'A'. Can you explain this answer?
Question Description
A particle of mass m carrying a positive charge q moves simple harmonically along x-axis under the action of a varying electric field E directed along x-axis. The motion of the particle is confined between x = 0 and x = 2l. The angular frequency of the motion is ω. Then, which of the following is correct?a)qE = - mω2(x - l)b)qE = mω2(x - l)c)Electric field to the right of origin is directed along +ve x-axis for all values of xd)Electric field to the right of origin is directed along -ve x-axis for all values of xCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particle of mass m carrying a positive charge q moves simple harmonically along x-axis under the action of a varying electric field E directed along x-axis. The motion of the particle is confined between x = 0 and x = 2l. The angular frequency of the motion is ω. Then, which of the following is correct?a)qE = - mω2(x - l)b)qE = mω2(x - l)c)Electric field to the right of origin is directed along +ve x-axis for all values of xd)Electric field to the right of origin is directed along -ve x-axis for all values of xCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle of mass m carrying a positive charge q moves simple harmonically along x-axis under the action of a varying electric field E directed along x-axis. The motion of the particle is confined between x = 0 and x = 2l. The angular frequency of the motion is ω. Then, which of the following is correct?a)qE = - mω2(x - l)b)qE = mω2(x - l)c)Electric field to the right of origin is directed along +ve x-axis for all values of xd)Electric field to the right of origin is directed along -ve x-axis for all values of xCorrect answer is option 'A'. Can you explain this answer?.
A particle of mass m carrying a positive charge q moves simple harmonically along x-axis under the action of a varying electric field E directed along x-axis. The motion of the particle is confined between x = 0 and x = 2l. The angular frequency of the motion is ω. Then, which of the following is correct?a)qE = - mω2(x - l)b)qE = mω2(x - l)c)Electric field to the right of origin is directed along +ve x-axis for all values of xd)Electric field to the right of origin is directed along -ve x-axis for all values of xCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particle of mass m carrying a positive charge q moves simple harmonically along x-axis under the action of a varying electric field E directed along x-axis. The motion of the particle is confined between x = 0 and x = 2l. The angular frequency of the motion is ω. Then, which of the following is correct?a)qE = - mω2(x - l)b)qE = mω2(x - l)c)Electric field to the right of origin is directed along +ve x-axis for all values of xd)Electric field to the right of origin is directed along -ve x-axis for all values of xCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle of mass m carrying a positive charge q moves simple harmonically along x-axis under the action of a varying electric field E directed along x-axis. The motion of the particle is confined between x = 0 and x = 2l. The angular frequency of the motion is ω. Then, which of the following is correct?a)qE = - mω2(x - l)b)qE = mω2(x - l)c)Electric field to the right of origin is directed along +ve x-axis for all values of xd)Electric field to the right of origin is directed along -ve x-axis for all values of xCorrect answer is option 'A'. Can you explain this answer?.
Solutions for A particle of mass m carrying a positive charge q moves simple harmonically along x-axis under the action of a varying electric field E directed along x-axis. The motion of the particle is confined between x = 0 and x = 2l. The angular frequency of the motion is ω. Then, which of the following is correct?a)qE = - mω2(x - l)b)qE = mω2(x - l)c)Electric field to the right of origin is directed along +ve x-axis for all values of xd)Electric field to the right of origin is directed along -ve x-axis for all values of xCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A particle of mass m carrying a positive charge q moves simple harmonically along x-axis under the action of a varying electric field E directed along x-axis. The motion of the particle is confined between x = 0 and x = 2l. The angular frequency of the motion is ω. Then, which of the following is correct?a)qE = - mω2(x - l)b)qE = mω2(x - l)c)Electric field to the right of origin is directed along +ve x-axis for all values of xd)Electric field to the right of origin is directed along -ve x-axis for all values of xCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A particle of mass m carrying a positive charge q moves simple harmonically along x-axis under the action of a varying electric field E directed along x-axis. The motion of the particle is confined between x = 0 and x = 2l. The angular frequency of the motion is ω. Then, which of the following is correct?a)qE = - mω2(x - l)b)qE = mω2(x - l)c)Electric field to the right of origin is directed along +ve x-axis for all values of xd)Electric field to the right of origin is directed along -ve x-axis for all values of xCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A particle of mass m carrying a positive charge q moves simple harmonically along x-axis under the action of a varying electric field E directed along x-axis. The motion of the particle is confined between x = 0 and x = 2l. The angular frequency of the motion is ω. Then, which of the following is correct?a)qE = - mω2(x - l)b)qE = mω2(x - l)c)Electric field to the right of origin is directed along +ve x-axis for all values of xd)Electric field to the right of origin is directed along -ve x-axis for all values of xCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A particle of mass m carrying a positive charge q moves simple harmonically along x-axis under the action of a varying electric field E directed along x-axis. The motion of the particle is confined between x = 0 and x = 2l. The angular frequency of the motion is ω. Then, which of the following is correct?a)qE = - mω2(x - l)b)qE = mω2(x - l)c)Electric field to the right of origin is directed along +ve x-axis for all values of xd)Electric field to the right of origin is directed along -ve x-axis for all values of xCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A particle of mass m carrying a positive charge q moves simple harmonically along x-axis under the action of a varying electric field E directed along x-axis. The motion of the particle is confined between x = 0 and x = 2l. The angular frequency of the motion is ω. Then, which of the following is correct?a)qE = - mω2(x - l)b)qE = mω2(x - l)c)Electric field to the right of origin is directed along +ve x-axis for all values of xd)Electric field to the right of origin is directed along -ve x-axis for all values of xCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup