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The image of an object formed by a lens is of magnification 1. If the distance between the object and its image is 60 cm. What is the focal length. If the object is moved 20 cm towards the lens where would the image be formed?
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The image of an object formed by a lens is of magnification 1. If the ...
Image with magnification -1 means image is inverted and of the same size.
Therefore, object is at 2F and the image is also at 2F on the other side of the lens.
Therefore, distance between the object and its image is 4f=60cm
=> f=15 cm
Object distance 2f= 30 cm, if the object is shifted  towards the lens by 20 cm, the new obiect diitance
=30 cm-20 cm=10 cm.

This distance is less than the focal length, and the image formed in this case would be virtual, erect and will form on the same side as the object.
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The image of an object formed by a lens is of magnification 1. If the ...


Calculating the Focal Length:
- Given magnification, m = 1
- Distance between object and image, d = 60 cm
- Using the magnification formula: m = -d'/d, where d' is the image distance
- Since m = 1, we have: 1 = -d'/60
- Solving for d', we get: d' = -60 cm
- Focal length, f = |d'|/2 = 30 cm

Image Formation when Object is Moved:
- When the object is moved 20 cm towards the lens, its new distance from the lens would be 40 cm (60 cm - 20 cm)
- Using the lens formula: 1/f = 1/d' + 1/d
- Substituting the new values: 1/30 = 1/d' + 1/40
- Solving for d', we get: d' = 120 cm
- Since the image distance is positive, the image is formed on the same side as the object, but farther away from the lens compared to the initial position.
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The image of an object formed by a lens is of magnification 1. If the distance between the object and its image is 60 cm. What is the focal length. If the object is moved 20 cm towards the lens where would the image be formed?
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