An object is placed at a distance of 8 cm from a convex mirror of foca...
U=-8 cm
f=12cm
nature of image=?
v=?
by mirror formula-
1/f=1/v+1/u
1/12=1/v+1/-8
5/24=1/v
v=24/5
v=4.8cm
nature of the image is virtual erect and magnified
An object is placed at a distance of 8 cm from a convex mirror of foca...
Given:
Distance of the object, u = -8 cm
Focal length of the convex mirror, f = 12 cm
To find:
Position and nature of the image formed
Solution:
We know that the mirror formula is given by:
1/f = 1/v + 1/u
Where,
v = distance of the image from the mirror
Substituting the given values in the formula, we get:
1/12 = 1/v + 1/-8
Solving for v, we get:
v = -24 cm
The negative sign indicates that the image is formed behind the mirror.
Position of the image:
Distance of the image, v = -24 cm
The image is formed at a distance of 24 cm behind the mirror.
Nature of the image:
To determine the nature of the image, we use the mirror formula again.
1/f = 1/v + 1/u
Substituting the values of u and v, we get:
1/12 = 1/-24 + 1/-8
Simplifying the equation, we get:
1/12 = -1/24
Since the equation is not valid, we cannot determine the nature of the image.
Conclusion:
The image is formed at a distance of 24 cm behind the convex mirror. However, the nature of the image cannot be determined as the mirror formula is not valid.
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